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3 years ago

Which two vectors, when subtracted (i.e., when one vector is subtracted from the other), will have the largest magnitude?

Physics

1 answer:

FromTheMoon [43]3 years ago

7 0

Given: Please see the attached image below.

To be able to subtract vectors, we can either use the parallelogram method or the triangle method. Take note that the only difference is that alternatively adding vectors A and B, we will instead be adding A and – B. When we ponder of vector subtraction, we must anticipate about it in terms of adding a negative vector. A negative vector has the same magnitude as the original vector, however, it has an opposite direction.

So in this problem, the two vectors that will have the largest magnitude are A & F when subtracted (i.e., when one vector is subtracted from the other).

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ahrayia [7]

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3 years ago

A ball having a mass of 200 g is released from rest at a height of 400 mm above a very large fixed metal surface. If the ball re

AysviL [449]

Answer:

0.9

Explanation:

h = 400 mm, h' = 325 mm

Let the coefficient of restitution be e.

h' = e^2 x h

325 = e^2 x 400

e^2 = 0.8125

e = 0.9

5 0

3 years ago

3. A car has a mass of 2.50 x 10^3 kg. If the force acting on the car is 7.65 x 10^3 N to the

const2013 [10]

Answer:

3.06m/s² to the east

Explanation:

Given parameters:

Mass of car = 2.5 x 10³kg

Force acting on the car = 7.65 x 10³N

Unknown:

Acceleration of the car = ?

Solution:

From Newton's second law of motion:

Force = mass x acceleration

Acceleration = $\frac{Force }{mass}$ = $\frac{7.65 x 10^{3} }{2.5 x 10^{3} }$ = 3.06m/s² to the east

6 0

3 years ago

Two ships of equal mass are 110 m apart. What is the acceleration of either ship due to the gravitational attraction of the othe

dusya [7]

Answer:

Acceleration of the ship, $a=2.14\times 10^{-7}\ m/s^2$

Explanation:

It is given that,

Mass of both ships, $m=39000\ metric\ tons=39\times 10^6\ kg$

Distance between two ships, d = 110 m

The gravitational force between two ships is given by :

$F=G\dfrac{m^2}{d^2}$

$F=6.67\times 10^{-11}\ Nm^2/kg^2\times \dfrac{(39\times 10^6\ kg)^2}{(110\ m)^2}$

F = 8.38 N

Let a is the acceleration. Now, using second law of motion as :

$a=\dfrac{F}{m}$

$a=\dfrac{8.38\ N}{39\times 10^6\ kg}$

$a=2.14\times 10^{-7}\ m/s^2$

So, the acceleration of either ship due to the gravitational attraction of the other is $2.14\times 10^{-7}\ m/s^2$ . Hence, this is the required solution.

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3 years ago

Newton's first law of motion is sometimes called the law of _________.

Gre4nikov [31]

Newtons first law of motion is also known as the law of inertia

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3 years ago