The height for the tropopause is the tropopause is about 20 km (12 miles or 65,000 feet) above sea level. It's temperature typically, drops about 6.5° C with each increase in altitude of 1 kilometer (about 3.6° F per 1,000 feet).
For the 5.0Kg block with the force of 15 Newton, the coefficient of static friction (μ) comes out to be 0.306. Applying the formula F = μmg.
Static friction acts on stationary body/body at rest. Let μ be the coefficient of static friction between the block and the horizontal floor.
Using the formula: F = μmg
Where,
F = Force , m= mass of the block and g = gravity.
and values of: m= 5.0Kg, F= 15.0N, g= 9.8m/s²
We can get: μ = F/(mg)
μ = 15/49
μ =0.306
Therefore, coefficient of static friction (μ) = 0.306.
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Answer:
b
Explanation:
air mass surrounding the earth