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FrozenT [24]
3 years ago
7

Graph the function. f(x)=−1/5x+4

Mathematics
1 answer:
Ivenika [448]3 years ago
7 0
4 is y and -1/5 is x
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A circle is centered at the point (-7, -1) and passes through the point (8, 7).
Sergeu [11.5K]

we know the circle's center is at -7, -1, and we know the circle itself passes through 8,7, the distance from the center to a point on it is by definition its radius, therefore

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\\stackrel{center}{(\stackrel{x_1}{-7}~,~\stackrel{y_1}{-1})}\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{7})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}\\\\\\\stackrel{radius}{r}=\sqrt{[8-(-7)]^2+[7-(-1)]^2}\implies r=\sqrt{(8+7)^2+(7+1)^2}\\\\\\r=\sqrt{15^2+8^2}\implies  r=\sqrt{225+64}\implies \boxed{r=17}

and since we know that x = -15 for such a point, then

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2\qquad center~~(\stackrel{-7}{ h},\stackrel{-1}{ k})\qquad \qquad radius=\stackrel{17}{ r}\\\\\\\[x-(-7)]^2+[y-(-1)]^2=17^2\implies (x+7)^2+(y+1)^2=289\\\\\\\stackrel{\textit{since we know x = -15}}{(-15+7)^2+(y+1)^2=289}\implies (-8)^2+\stackrel{FOIL}{(y^2+2y+1^2)}=289\\\\\\64+y^2+2y+1=289\implies y^2+2y=224\implies y^2+2y-224=0\\\\\\(y+16)(y-14)=0\implies y=\begin{cases}-16\\14\end{cases}

since it's a circle, it touches x = -15 twice, check the picture below.

6 0
3 years ago
WILL MARK BRAINLIEST IF RIGHT POSTED TWICE PLZZZZZZZZZZZZZ
Anni [7]
7,8,6,5,9,10,20
Total:7
Even number:8,6,10,20
First pick:
4/7
Second pick:
3/6 or 1/2. As a result, the final answer is 2/7. Hope it help!
5 0
3 years ago
The zeros of a function are the values of x for which the function is equal to zero.
ikadub [295]

Answer:

g(x)=0  when x= 2 or when x= 5

The graph of g intercepts the x-axis at x= 2 and x= 5

The zeros of g are 2 and 5

Step-by-step explanation:

7 0
3 years ago
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