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FrozenT [24]
3 years ago
7

Graph the function. f(x)=−1/5x+4

Mathematics
1 answer:
Ivenika [448]3 years ago
7 0
4 is y and -1/5 is x
You might be interested in
Can someone help me find x.
Harman [31]

Answer:

Step-by-step explanation:

6x+9=63

6x=63-9

6x=54

x=54/6

x=9

I encourage you to figure out the justification yourself.

8 0
3 years ago
A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t
MakcuM [25]

Answer:

165.

Step-by-step explanation:

Since repetition isn't allowed, there would be 11 choices for the first donut, (11 - 1) = 10 choices for the second donut, and (11 - 2) = 9 choices for the third donut. If the order in which donuts are placed in the bag matters, there would be 11 \times 10 \times 9 unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type 3 \times 2 \times 1 = 6 times.

For example, if a bag includes donut of type x, y, and z, the count 11 \times 10 \times 9 would include the following 3 \times 2 \times 1 arrangements:

  • xyz.
  • xzy.
  • yxz.
  • yzx.
  • zxy.
  • zyx.

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count 11 \times 10 \times 9 by 3 \times 2 \times 1 = 6 to find the actual number of donut combinations:

\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of 3 objects from a set of 11 distinct objects:

\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

5 0
2 years ago
A flatbed truck is being loaded with steel girders weighing 1825 lbs each. How much will 15 of these girders weigh, combined?
saw5 [17]
I think I know how it's done!

You need to multiply 1825 by 15. You may want to show the work in this one.

1825•15 = 27,375

Thus, the truck will be loaded with 27,375 lbs of steel girders.

Hope this helps you succeed!
6 0
3 years ago
I need help! this is missing
mr Goodwill [35]

Answer:

top right

Step-by-step explanation:

if you solve an equation for a triangle using this method you'll get this result

6 0
1 year ago
Read 2 more answers
A new school has x day students and y boarding students.
guapka [62]

Given:

The fees for a day student are $600 a term.

The fees for a boarding student are $1200 a term.

The school needs at least $720000 a term.

To show:

That the given information can be written as x + 2y\geq 1200.​

Solution:

Let x be the number of day students and y be the number of boarding students.

The fees for a day student are \$600 a term.

So, the fees for x day students are \$600x a term.

The fees for a boarding student are \$1200 a term.

The fees for y boarding student are \$1200y a term.

Total fees for x day students and y boarding student is:

\text{Total fees}=600x+1200y

The school needs at least $720000 a term. It means, total fees must be greater than or equal to $720000.

600x+1200y\geq 720000

600(x+2y)\geq 720000

Divide both sides by 600.

\dfrac{600(x+2y)}{600}\geq \dfrac{720000}{600}

x+2y\geq 1200

Hence proved.

3 0
3 years ago
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