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Gala2k [10]
3 years ago
6

6x - 10y = -16 x + 20y = 19

Mathematics
1 answer:
Lena [83]3 years ago
4 0
This may be the right answer: x=-1 y=-11/5
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A nurse works in a military hospital from 1300 to 2000. What time of day does this nurse work?
vazorg [7]
Hello!

An easy way to find military time that is more than 12 is to subtract 12 from the number. For example, 14:00-12= 2:00 P.M.

In this case 13-12 is 1:00, and 20-12 is 8:00.

This nurse works from 1:00 P.M. to 8:00 P.M., or the afternoon.

I hope this helps!
4 0
3 years ago
Point O is the incenter of triangle ABC. Point O is the incenter of triangle A B C. Lines are drawn from the points of the trian
marissa [1.9K]

Answer:

No Options

∠QOB=45º

Step-by-step explanation:

we have that: point O=Incenter, sides S, Q, R they form right angles with the point O,  angle OBC = 15º and angle OCR=30º, find angle QOB

we know that the sum of all the internal angles of a triangle is 180º,  so

α =180-30-15-90=45º   and  β = 180-90-α  → β = 180-90-45 =45º,

Finally  β=∠QOB=45º

5 0
4 years ago
Read 2 more answers
How do you multiply 5 time one fourth
eduard

5x .25=1.25 or 1   1/2



8 0
3 years ago
Read 2 more answers
What values of a and b make the equation true?
mestny [16]

Answer:

3

Step-by-step explanation:

\sqrt{648} =\sqrt{2 * 2 * 2 * 3 * 3 * 3 * 3} \\\\=\sqrt{2^{3}*3^{4}}

a = 3 & b =4

6 0
3 years ago
A) explain how you can write and solve equations to find the measure of each angle
Ainat [17]

Answer:

A) For line <em>l = </em>(2x + 8°) + (5x - 10°) = 180° ....... (i)

For line <em>k</em> = (3x + 42°) + (x + 34°) = 180° ....... (ii)

B) In line <em>l, </em>two angles are = 60° and 120°

In line <em>k, </em>two angles are =  120° and 60°

Step-by-step explanation:

Requirement A

To find the measure of each angle, we have to use equation.

According to the graph, line <em>l </em>and<em> k </em>are parallel, therefore, both are straight angle. We know that a straight angle is equal to 180°. Therefore, line <em>l </em>and<em> k </em>are 180°. As both the line are intersected by line <em>j</em>, the lines are separated by two angles. So, the equation for line <em>l</em> is -

(2x + 8°) + (5x - 10°) = 180° ....... (i)

the equation for line <em>k</em> is -

(3x + 42°) + (x + 34°) = 180° ....... (ii)

Requirement B

For line "<em>l </em>"

By solving the equations, we can measure the angles

(2x + 8°) + (5x - 10°) = 180°

or, 2x + 8° + 5x - 10° = 180°

or, 7x - 2° = 180°

or, 7x = 180° + 2°

or, 7x = 182°

or, x = 182° ÷ 7 [Dividing both the sides by 7]

or, x = 26°

Therefore, 2x + 8° = 2 × 26° + 8° = 52° + 8° = 60°

the other angle is = 5x - 10° = 5 × 26° - 10° = 130° - 10° = 120°

For line "<em>k </em>"

(3x + 42°) + (x + 34°) = 180°

or, 3x + 42° + x + 34° = 180°

or, 4x + 76° = 180°

or, 4x = 180° - 76° [Deducting 76° from the both the sides]

or, 4x = 104°

or, x = 104° ÷ 4

Hence, x = 26°

Therefore, 3x + 42° = 3 × 26° + 42° = 78° + 42° = 120°

The other angle is = x + 34° = 26° + 34° = 60°

5 0
3 years ago
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