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Anika [276]
3 years ago
9

A nontoxic furniture polish can be made by combining vinegar and olive oil. The amount of oil should be three times the amount o

f vinegar. How much of each ingredient is needed in order to make 30oz of furniture​ polish?
Mathematics
1 answer:
DENIUS [597]3 years ago
7 0
To answer this question you will use ratios. The information given gives us a part to part ratio of 1 part vinegar for every 3 parts oil.

Because the total amount of furniture polish is 30 ounces, we will need to write one part vinegar to three parts oil as a part to part to whole ratio.

Use this information then and create an equivalent ratio with a total of 30 ounces. See below.

1 vinegar (x7.5) = 7.5 ounces
3 oil. (X7.5). = 22.5 ounces
4 total (x7.5). = 30 ounces

You will need 7.5 ounces of vinegar and a 22.5 ounces of oil.
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What equals 7 in multiplication
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Enter the equation of the line in slope-intercept form. The line parallel to y = 7 6 x + 6 that passes through (−6, 0). The equa
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Attached solution with steps.

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3 years ago
Find n(A) for A={0,1,2,3,...,2000}
miskamm [114]
There are 2001 items in that set.

So n(A) = 2001

We can individually count them all out, which is very slow and tedious, or we can use the formula
n-m+1

where,
m = starting value
n = ending value

In this case,
m = 0
n = 2000
So,
n-m+1 = 2000-0+1 = 2001

This formula only works if we increase the number by 1 each time (eg: 6, 7, 8, etc)
7 0
3 years ago
How many ways can eight letters be arranged into groups of five where order matters and the first two letters are already chosen
fenix001 [56]

Answer:

120

Step-by-step explanation:

Since we're dealing with a problem where the order matters and the first two letters are already chosen we need to subtract the number of letters and the number of available slots per group.

We use the permutation formula to find the answer, but before that let's check values.

n = 8

k = 5

Now since there are two letters already chosen we have to deduct two from both the value of n and k.

n = 6

k = 3

Now we can use the permutation formula:

_{n}P_{k}=\dfrac{n!}{(n-k)!}

_{6}P_{3}=\dfrac{6!}{6-3)!}

_{6}P_{3}=\dfrac{6!}{3!}

_{6}P_{3}=\dfrac{6*5*4*3*2*1}{3*2*1}

The 3*2*1 cancels out and leaves us with:

_{6}P_{3}=6*5*4

_{6}P_{3}=120

So there are 120 possible ways to arrange eight letters into groups of five where order matters and the first two letters are already chosen.

6 0
3 years ago
Read 2 more answers
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