40 + 60 = 100
Hundrends place
Answer:
The decision rule is
Fail to reject the null hypothesis
The conclusion is
There is no sufficient evidence to show that the designer's claim of a better shoe is supported by the trial results.
Step-by-step explanation:
From the question we are told that
The population mean is 
The sample size is n = 25
The sample mean is 
The standard deviation is 
Let assume the level of significance of this test is 
The null hypothesis is 
The alternative hypothesis is 
Generally the degree of freedom is mathematically represented as

=> 
=> 
Generally the test statistics is mathematically represented as

=> 
=> 
Generally from the student t distribution table the probability of obtaining
to the right of the curve at a degree of freedom of
is

From the value obtained we see that
hence
The decision rule is
Fail to reject the null hypothesis
The conclusion is
There is no sufficient evidence to show that the designer's claim of a better shoe is supported by the trial results.
length is 8m
Width is 6.5m
<u>Explanation:</u>
Let, width = b
So, length = 2b-5
area = 52
We know,
area of rectangle = length X width
So,
= 
On solving the above equation, we get
Width, b = 6.5m
length, l = 8m
Answer:

Step-by-step explanation:
We are given

Let's assume it can be factored as

now, we can multiply right side
and then we can compare it


now, we can compare coefficients



now, we can find all possible factors of 48
and then we can assume possible prime factors of 48





Since, we have to find the largest value of n
So, we will get consider larger value of r because of 5r
and because n is negative of 5r+s
so, we will both n and r as negative
So, we can assume
r=-48 and s=-1
so, we get


When a linear equation is in the form y = mx + c, the c, or constant, is the intercept on the y axis, meaning it crosses the y axis at (0, 1).
The gradient (1/3 in this case) is how much the y increments (or decrements) per increase of 1 of the value of x.
This would mean that there would be one point at (0, 1), and another at (3, 2). Draw a line from these two points and beyond, and that is the graph sketched.