Answer:
Distance between Montpelier and Columbia is 1020
Step-by-step explanation:
51 mi/hr average:
d = 51 t
60 mi/hr average:
d t = 60*(t-3)
Substitute (1) into (2)
51 t = 60*(t-3)
51 t = 60 t + 180
9 t = 180
t = 20
d = 51 t
= 51 (20)
= 1020
let see distance is 1020 lets check
51 t = 60 * (t-3)
51 (20)= 60* (20-3)
1020 = 60*17
1020 = 1020
Answer:
x = 12.8
Step-by-step explanation:
i use this calculator to find triangle measurements as long as you know like three values it works
https://www.calculator.net/triangle-calculator.html?vc=90&vx=&vy=10&va=38&vz=&vb=&angleunits=d&x=79&y=19
ik sending a link is hecka sus but you can just look up triangle calculator and it'll pop up
Answer:
Figure A
Step-by-step explanation:
Hope it helps.
The length of AC is congruent to WY
d = 10