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2 years ago

14

Can somebody please help me with the question below and please explain how to find the answer? plz, I'm studying for a test plzz

zz help!!!

1 answer:

blagie [28]2 years ago

3 0

Answer:

-10/9 < -2/3 < 4/6 < 6/5 < 5/4

(hope this helps!)

Step-by-step explanation:

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Please help I will be very grateful for this

mixer [17]

Answer:

____________

the answer is B

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explanation

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

(x^2 - 2x) - 3xy + 6y

Factor out the greatest common factor (GCF) from each group.

x(x - 2) - 3y (x - 2)

Factor the polynomial by factoring out the greatest common factor, x - 2

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3 years ago

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∠1 and ∠2 are complementary angles. m∠1=13° What is the measure of ∠2 ?

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2 years ago

The product of 8 and the difference of 3 and a number

Neko [114]

Answer:

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Step-by-step explanation:

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3 0

2 years ago

Find the sum of each series, if it exists<br>91 + 85 + 79 + … + (29)

Natali [406]

Answer:

651.

Step-by-step explanation:

Note: In the given series it should be -29 instead of 29 because 29 cannot be a term of AP whose first term is 91 and common difference is -6.

Consider the given series is

$91+85+79+...+(-29)$

It is the sum of an AP. Here,

First term = 91

Common difference = 85 - 91 = -6

Last term = -29

nth term of an AP is

$a_n=a+(n-1)d$

where, a is first term and d is common difference.

$-29=91+(n-1)(-6)$

$-29-91=(n-1)(-6)$

$\dfrac{-120}{-6}=(n-1)$

$20=(n-1)$

$n=20+1=21$

Sum of AP is

$Sum=\dfrac{n}{2}[\text{First term + Last term}]$

$Sum=\dfrac{21}{2}[91+(-29)]$

$Sum=\dfrac{21}{2}[62]$

$Sum=651$

Therefore, the sum of given series is 651.

5 0

2 years ago

6.17 greater or less 61 87/100

Mrrafil [7]

Answer:

Less

Step-by-step explanation:

$6.17 < 6.187$

3 0

2 years ago