Hi there!
Parabola x² = 12y
→ x² = 4ay
→ 4a = 12
→ a = 12÷4
→ a = 3
So, the co-ordinates of the focus is:-
S(0,a)=(0,3)
→ Let AB be the latus rectum of the given parabola.
→ Coordinates of end-points of latus rectum are (-2a,a), (2a,a)
→ Coordinates of A are (-6,3), while B's coordinates are (6,3).
→ ∆OAB are O(0,0), A(-6,3), B(6,3)
Area of ∆OAB is :-
(<em>Solving part attached as image</em>)
=> <u>1</u><u>8</u><u> </u><u>unit</u>² is the required answer.
It depends on how much the computer game costs.
<h3>
Answer: x = -1</h3>
Explanation:
The given quadratic is in the form y = ax^2 + bx + c
We have a = 1, b = 2, c = 2
This then leads to
h = -b/(2a)
h = -2/(2*1)
h = -1
This is the x coordinate of the vertex (h,k)
The axis of symmetry is the vertical line passing through the vertex. So it must share the x value in question.
Meaning the axis of symmetry is x = -1. Every point on this vertical line has an x coordinate of -1. This line of symmetry splits the parabola into two equal mirrored halves.
I recommend using a graphing tool like Desmos to visually confirm the answer.
Answer:
yes I think 6 is a solution to the equation
