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Sav [38]
2 years ago
10

How do u find equivalent fractions

Mathematics
2 answers:
adelina 88 [10]2 years ago
8 0
You can make equivalent fractions by multiplying or dividing both top and bottom by the same amount.
Kipish [7]2 years ago
5 0
You cross multiply
a   c
- = -
b   d
if ad equals bc, then the fractions are equivalent
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Which equation shows function notation for a vertical stretch of factor 2 and shift right 5 units? *
liubo4ka [24]

Answer: I am doing an giveaway for and iphone 11 pro max (black)

Step-by-step explanation: first person who message me gets it be the first

7 0
3 years ago
Find ten rational numbers between -1 by 5 and 1 by 2 ​
uysha [10]

Answer:

Step-by-step explanation:

First both the rational numbers should have same denominators. So, find least common denominator

Least common denominator is 10

\frac{-1}{5}=\frac{-1*2}{5*2}=\frac{-2}{10}\\\\\\\frac{1}{2}=\frac{1*5}{2*5}=\frac{5}{10}\\\\\\

Now multiply  the numerator  and denominators of the both the numbers by 10.

\frac{-2*10}{10*10}= \frac{-20}{100} \ and \ \frac{5*10}{10*10}=\frac{50}{100}\\\\\\Now\ 10 \ rational  \ numbers \ between\frac{-20}{10} \ and \ \frac{50}{100} \ is \\\\\\\frac{-19}{100},\frac{-18}{100},\frac{-17}{100},\frac{-16}{100}.\frac{-15}{100},\frac{-14}{100},\frac{-13}{100},\frac{-12}{100},\frac{-11}{100};\frac{-10}{100}

8 0
2 years ago
Solve <br> (6x + 5) - (x + 3)
Pie

Answer:

5x+2

Step-by-step explanation:

6x-x=5x and 5-3=2

so 5x+2 is the answer.

4 0
3 years ago
Consider the sets below. u = {x | x is a real number} a = {x | x is an odd integer} r = {x | x = 3, 7, 11, 27} is r ⊂ a?
-BARSIC- [3]

The correct option is (B) yes because all the elements of set R are in set A.

<h3>What is an element?</h3>
  • In mathematics, an element (or member) of a set is any of the distinct things that belong to that set.

Given sets:

  1. U = {x | x is a real number}
  2. A = {x | x is an odd integer}
  3. R = {x | x = 3, 7, 11, 27}

So,

  • A = 1, 3, 5, 7, 9, 11... are the elements of set A.
  • R ⊂ A can be understood as R being a subset of A, i.e. all of R's elements can be found in A.
  • Because all of the elements of R are odd integers and can be found in A, R ⊂ A is TRUE.

Therefore, the correct option is (B) yes because all the elements of set R are in set A.

Know more about sets here:

brainly.com/question/2166579

#SPJ4

The complete question is given below:
Consider the sets below. U = {x | x is a real number} A = {x | x is an odd integer} R = {x | x = 3, 7, 11, 27} Is R ⊂ A?

(A) yes, because all the elements of set A are in set R

(B) yes, because all the elements of set R are in set A

(C) no because each element in set A is not represented in set R

(D) no, because each element in set R is not represented in set A

8 0
1 year ago
A box 6 purple marbles, 5 black marbles, and 15 green marbles. Write two different situations; a dependent and independent event
Lerok [7]
The most probable answer if you pull one out would be you pull a green marble.
5 0
2 years ago
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