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pshichka [43]
3 years ago
13

Experiments using "optical tweezers" measure the elasticity of individual DNA molecules. For small enough changes in length, the

elasticity has the same form as that of a spring. A DNA molecule is anchored at one end, then a force of 1.5 nN (1.5 x 10-9 N) pulls on the other end, causing the molecule to stretch by 5.0 nm (5.0 x 10-9 m). What is the spring constant of that DNA molecule?
Biology
1 answer:
Lapatulllka [165]3 years ago
5 0

Answer:

The spring constant of DNA molecule is 0.3\frac{N}{m}

Explanation:

As we know ,

Formula for spring constant

F = -kX\\

Where,

F = Force exerted on the DNA molecule in Newton

k = spring constant in \frac{Newton}{Meter}

X = displacement in meters

Substituting the given values in above equation, we get -

1.5 * 10^{-9} = -k * 5.0* 10^{-9}\\k = 0.3\frac{N}{m}

Thus, the spring constant of DNA molecule is 0.3\frac{N}{m}

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