According to the vertex and the directrix of the given parabola, the equation is:
<h3>What is the equation of a parabola given it’s vertex?</h3>
The equation of a quadratic function, of vertex (h,k), is given by:
In which a is the leading coefficient.
The directrix is at y = k + 4a.
In this problem, the vertex is (1,4), hence:
The directrix is at y = 7, hence:
Hence, the equation is:
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To determine the ratio, we need to know the formula of the area of an hexagon in terms of the length of its sides. We cannot directly conclude that the ratio would be 3, the same as that of the ratio of the lengths of the side, since it may be that the relationship of the area and length is not equal. The area of a hexagon is calculated by the expression:
A = (3√3/2) a^2
So, we let a1 be the length of the original hexagon and a2 be the length of the new hexagon.
A2/A1 = (3√3/2) a2^2 / (3√3/2) a1^2
A2/A1 = (a2 / a1)^2 = 3^2 = 9
Therefore, the ratio of the areas of the new and old hexagon would be 9.
The given equation has no solution when K is any real number and k>12
We have given that
3x^2−4x+k=0
△=b^2−4ac=k^2−4(3)(12)=k^2−144.
<h3>What is the condition for a solution?</h3>
If Δ=0, it has 1 real solution,
Δ<0 it has no real solution,
Δ>0 it has 2 real solutions.
We get,
Δ=k^2−144 here Δ is not zero.
It is either >0 or <0
Δ<0 it has no real solution,
Therefore the given equation has no solution when K is any real number.
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Answer:
describe the relationship between what
Step-by-step explanation:
