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3 years ago

In factoring by grouping, what would you have for step 3 for the following?

Mathematics

2 answers:

MA_775_DIABLO [31]3 years ago

8 0

Answer:

Factor out the x+5

(x+5)(x^2+4)

Step-by-step explanation:

Step 1: x^3 +5x^2 +4x+20

Step 2: x^2 (x+5)+4(x+5)

Step 3: Factor out the x+5

(x+5)(x^2+4)

solong [7]3 years ago

6 0

Answer:

Step 3: (x^2 + 4)(x + 5)

Step-by-step explanation:

Step 1: x^3 +5x^2 + 4x+20

Step 2: x^2 (x+5) + 4(x+5)

Step 3: (x^2 + 4)(x + 5)

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3 years ago

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9 months ago

The attention span of children (ages 3 to 5) is claimed to be Normally distributed with a mean of 15 minutes and a standard devi

Agata [3.3K]

Answer:

If the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 minutes

Sample size, n = 10

Alpha, α = 0.05

Population standard deviation, σ = 4 minutes

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 15\text{ minutes}\\H_A: \mu > 15\text{ minutes}$

Since the population standard deviation is given, we use one-tailed z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Now, $z_{critical} \text{ at 0.05 level of significance for one tail} = 1.64$

Thus, we would reject the null hypothesis if the z-statistic is greater than this critical value.

Thus, we can write:

$z_{stat} = \displaystyle\frac{\bar{x} - 15}{\frac{4}{\sqrt{10}} } > 1.64\\\\\bar{x} - 15>1.64\times \frac{4}{\sqrt{10}}\\\bar{x} - 15>2.07\\\bar{x} > 15+2.07\\\bar{x} > 17.07$