All categories

3 years ago

Can anyone help with problem 9.9 in the middle pls

Mathematics

1 answer:

ELEN [110]3 years ago

3 0

Answer:

Angle 1: 53

Angle 2: 72

Angle 3: 55

Angle 4: 127

Angle 5: 53

Angle 6: 66

Angle 7: 125

You might be interested in

Identify the coefficient(s) of the variable in the expression below.

tankabanditka [31]

Answer:

Step-by-step explanation:

25 and 6

Coefficient is the number in front of the unknown variable

3 0

3 years ago

Read 2 more answers

Which fraction is closer to 0 than 1

scoundrel [369]

Answer:

5/12

Step-by-step explanation:

Since 1/2 is the same distance from zero and one, we can use it to judge whether a fraction is closer to 0 or 1.

Since 5/8 is greater than 4/8 which is 1/2, it is closer to 1.

Since 8/10 is greater than 5/10 which is 1/2, it is closer to 1.

Since 5/12 is less than 6/12 which is 1/2, it is closer to 0.

So our answer is C. 5/12

3 0

3 years ago

Help with question B please No scam brainliest will be given

erma4kov [3.2K]

Are you still looking for a answer? If so I would love to give you mine.

4 0

3 years ago

F(x)=|x-5|+2 Evaluate f(3). A.) 10 B.) 0 C.) 4 D.) 6

Talja [164]

F(x)=|x-5|+2
plug it in

so f(3)
f3)=|3-5|+2
solve whats inside first
|-2|+2
since its absolute value its actually positive
2+2
4

Your answer is C.) 4

4 0

3 years ago

An insurance company sells automobile liability and collision insurance. Let X denote the percentage of liability policies that

qaws [65]

Answer:

-764.28

Step-by-step explanation:

Given the joint cumulative distribution of X and Y as

$F(x,y) = \frac{xy(x+y)}{2000000}\ \ \ \, \ 0\leq x100, 0\leq y\leq 100$

#First find $F_x$ and probability distribution function , $f_x(x)$ :

$F_x(x)=F(x,100)\\\\\\=\frac{100x(x+100)}{2000000}\\\\\\\\=\frac{100x^2+10000x}{2000000}\\\\\\=>f_x(x)=\frac{x}{10000}+\frac{1}{200}$

#Have determined the probability distribution unction , $f_x(x)$ , we calculate the Expectation of the random variable X:

$E(X)=\int\limits^{100}_0 \frac{x^2}{10000}+\frac{x}{200} dx \\\\\\\\=|\frac{x^3}{30000}+\frac{x^2}{400}|\limits^{100}_0\\\\=58.33\\\\$

#We then calculate $E(X^2)$ :

$E(X^2)=\int\limits^{100}_0 \frac{x^3}{10000}+\frac{x^2}{200}\ dx\\\\=\frac{x^4}{40000}+\frac{x^3}{600}|\limits^{100}_0=4166.67\\\\Var(X)=E(X^2)-(E(X))^2=4166.67-58.33^2\\\\Var(X)=764.28$

Hence, the Var(X) is 764.28

4 0

3 years ago