3/8 divided by 5/8 = 3/5
hope this helps :D
Answer:

Step-by-step explanation:
To find a line that is perpendicular to 8x + 3y = -6 and goes through (-24, 2), lets first find what the line's slope would be.
We can find this by finding the slope of 8x + 3y = -6 and taking the negative reciprocal of it.
We can find the slope of that line by putting it in slope-intercept form:
8x + 3y = -6
Subtract 8x from both sides.
3y = -6 - 8x
Divide both sides by 3.


So the slope of that line would be -8/3.
The negative reciprocal of -8/3 would be 3/8.
Now we know that the new line would have to pass through the point (-24, 2). We can use this point and write the equation in point-slope form:

Now lets change this into slope-intercept form. Add 2 to both sides.

Distribute the 3/8.

Simplify.

And now we have our equation in slope-intercept form.
I hope you find this helpful.
Answer:
5
Step-by-step explanation:
9514 1404 393
Answer:
B. 3x² +2 = 0
Step-by-step explanation:
The equation of A has a couple of real roots. We're pretty sure there are complex numbers that will satisfy this equation, but we don't know how to find them. (We suspect a typo, and that the equation is supposed to be 2x² +1 = 7x, which has only real roots.)
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The equation of B can be rewritten as ...
x² = -2/3
This will have complex roots.
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The discriminants of both equations C and D are positive, so those have only real roots.
2x² -5x -1 ⇒ d = (-5)² -4(2)(-1) = 33
3x² -6x -1 ⇒ d = (-6)² -4(3)(-1) = 48