Can you help me on problem number 16.

Mathematics

2 answers:

Gnom [1K]2 years ago

7 0

You can divide it and see what you get for it

Ganezh [65]2 years ago

6 0

2,552or 960 not sure.

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When an amount of heat Q (in kcal) is added to a unit mass (kg) of a

lisov135 [29]

Answer:

The change in temperature per minute for the sample, dT/dt is 71. $\overline {6}$ °C/min

Step-by-step explanation:

The given parameters of the question are;

The specific heat capacity for glass, dQ/dT = 0.18 (kcal/°C)

The heat transfer rate for 1 kg of glass at 20.0 °C, dQ/dt = 12.9 kcal/min

Given that both dQ/dT and dQ/dt are known, we have;

$\dfrac{dQ}{dT} = 0.18 \, (kcal/ ^{\circ} C)$

$\dfrac{dQ}{dt} = 12.9 \, (kcal/ min)$

Therefore, we get;

$\dfrac{\dfrac{dQ}{dt} }{\dfrac{dQ}{dT} } = {\dfrac{dQ}{dt} } \times \dfrac{dT}{dQ} = \dfrac{dT}{dt}$

$\dfrac{dT}{dt} = \dfrac{\dfrac{dQ}{dt} }{\dfrac{dQ}{dT} } = \dfrac{12.9 \, kcal / min }{0.18 \, kcal/ ^{\circ} C } = 71.\overline 6 \, ^{\circ } C/min$

For the sample, we have the change in temperature per minute, dT/dt, presented as follows;

$\dfrac{dT}{dt} = 71.\overline 6 \, ^{\circ } C/min$

8 0

2 years ago

Please answer I am struggling

blsea [12.9K]

(For question 1 you have to do it yourself, get a ruler and measure the actual length of the drawing, then multiply it by 8 to get the actual dimensions in the exercise. )

Example, if you measure 4 inches, the actual dimension will be 4 x 8 = 32 ft

2. (Scale drawing 1:5 is that every 1 (length units) will be equal to 5(length units) in the actual dimensions)

Model : 3ft ; 7m
Actual : 15ft ; 35m (corresponding)

Actual : 20yd ; 12.5 cm
Model : 4yd ; 2.5 cm

6. 1.5 ft = 1.5 x 12 = 18 inches.
The model is 3 inches, and the actual rose is 18 inches -> The scale of the drawing is 6. (enlargement)

Same goes to the scale factor, but this time is the quotient of the corresponding side -> 3 : 18 = 1:6.

(If I got any parts wrong just tell me, I actually kinda forgot these kind of stuff)