Answer: 9
Step-by-step explanation: 4.5=.5xZ. 4.5/.5=9=z
Answer:
The 95% confidence interval for the mean savings is ($60.54, $81.46).
Step-by-step explanation:
As there is no information about the population standard deviation of savings and the sample is not large, i.e. <em>n</em> = 20 < 30, we will use a <em>t</em>-confidence interval.
The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:
For the data provided compute the sample mean and standard deviation as follows:
The critical value of <em>t</em> for <em>α</em> = 0.05 and (n - 1) = 19 degrees of freedom is:
*Use a <em>t</em>-table for the value.
Compute the 95% confidence interval for the mean savings as follows:
Thus, the 95% confidence interval for the mean savings is ($60.54, $81.46).
Answer:
You can use estimation to check for reasonableness when you have math problems with all numbers. When you do use estimation, it won't tell you whether you actually have the correct answer, but it will tell you if you're close and your answer is probably right.
Step-by-step explanation:
Answer:
1. 0.507
2. 5.006
3. 9.062
Step-by-step explanation:
If a value has “thousandths” in the question, the decimal place goes 4 places to the left: ex. 0.007.
Well it'll take 40 weeks til you run out of money..... Was that the answer you're looking for?