Answer:
Step-by-step explanation:
<u>Given</u>
- Monthly payment P = $300
- Time t = 3 years = 36 months
- Number of payments n = 36
- Interest rate r = 12% PA = 1% per month = 0.01 times
<u>Use loan payment formula:</u>
- P = r(PV) / (1 - (1 + r)⁻ⁿ),
- where P- monthly payment, PV - present value (amount of the loan), r -rate of interest, n- number of payments
<u>Substitute values and solve for PV:</u>
- 300 = (0.01*PV) / (1 - (1 + 0.01)⁻³⁶)
- PV = 300*(1 - 1.01⁻³⁶ )/ 0.01
- PV = 9032.25 ≈ $9000 (rounded to the nearest hundred dollars)
X is Kevin; Y is Dan
X = 3Y
X - 4 = 5(Y - 4)
3Y - 4 = 5(Y - 4)
3Y - 4 = 5Y - 20
+ 4 +4
4 cancels each other out.
3Y = 5Y - 16
- 5 -5
5 cancels each other out.
-2Y = -16
/2 /2
Y = 8
X = 3Y;
X = 3 x 8;
Thus,
X = 24;
Kevin(x) is 24
Answer:
x = ± 12
Step-by-step explanation:
Given
f(x) = x² - 144
To find the roots set f(x) = 0, that is
x² - 144 = 0 ( add 144 to both sides )
x² = 144 ( take the square root of both sides )
x = ±
= ± 12
Answer:
a) Null and alternative hypotheses are:
: mu=183 days
: mu>183 days
b) If the true mean is 190 days, Type II error can be made.
Step-by-step explanation:
Let mu be the mean life of the batteries of the company when it is used in a wireless mouse
Null and alternative hypotheses are:
: mu=183 days
: mu>183 days
Type II error happens if we fail to reject the null hypothesis, when actually the alternative hypothesis is true.
That is if we conclude that mean life of the batteries of the company when it is used in a wireless mouse is at most 183 days, but actually mean life is 190 hours, we make a Type II error.
Answer:
A. <
B. =
C. >
D. <
Step-by-step explanation: