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3 years ago

Which is f(5) for the function -2x + 2x-3?

Mathematics

2 answers:

nata0808 [166]3 years ago

6 0

The anwser is -3
hope this helps

slava [35]3 years ago

3 0

Answer:

f(5)=-3

Step-by-step explanation:

5 is the value of x. So all you would have to do is substitute x with 5 in the equation. Once you do that you would get f(5)=-2(5)+2(5)-3. Then use distributive property which is basically the number on the left side of the parenthesis multiplying the number inside of the parenthesis. Once you do that you'll get f(5)=-10+10-3. Then all you have to do is solve the equation. Once you solve it, you should get an answer of f(5)=-3. Hope this helped. :)

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3 years ago

The ratio of students who prefer comedic plays to students who prefer romantic plays in the drama club is 2 to 3. If all student

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3 years ago

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4 years ago

Find all pairs of real numbers $(x,y)$ such that $x + y = 6$ and $x^2 + y^2 = 28$. if you find more than one pair, then list you

vivado [14]

1. $x^2+y^2=28$ and x+y=6

2. x^2+y^2 and x+y remind us of the formula: $(x+y)^{2}= x^2+y^2+2xy$

substituting we get:

$6^{2}= 28+2xy$

2xy=36-28
xy=8/2=4

3 Let's solve the system of equations i)x+y=6 and ii)xy=4

substitute y=4/x in (i):

$x+ \frac{4}{x} =6$

multiply all sides by x:

$x^{2} +4=6x$

$x^{2} -6x+4=0$

complete the square:

$x^{2} -6x+4=x^{2} -2*3x+9-9+4= (x-3)^{2}-5=0$

$x-3=\sqrt{5}$ or $x-3=-\sqrt{5}$

$x=3+\sqrt{5}$ or $x=3-\sqrt{5}$

so from x+y=6, y=6-x

case 1, $x=3+\sqrt{5}$ gives $y=3-\sqrt{5}$

case 2, $x=3-\sqrt{5}$ gives $y=3+\sqrt{5}$

Answer:

$(3-\sqrt{5}, 3+\sqrt{5})$ , $(3+\sqrt{5}, 3-\sqrt{5})$

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3 years ago