Answer:
<h2><u>
=</u>
<u>
57
/ 514 </u>
<u>
(Decimal: 0.110895)</u></h2>
Step-by-step explanation:
57
/ 514
<u>= 57
/ 514
</u>
<u>(Decimal: 0.110895)</u>
<u></u>
<u></u>
<u></u>
<u></u>
<u></u>
<u></u>
<u></u>
<u></u>
<u></u>
<h2><u>
And if that is not what you are looking for here: </u></h2><h2><u>
</u></h2>
Rewrite the equation as
x
/14
= 5/
7
. x/
14
= 5/
7
Multiply both sides of the equation by
14.14 ⋅ x
/14
= 14
⋅
5
/7
Simplify both sides of the equation.
Tap for fewer steps...
Cancel the common factor of 14
.
Cancel the common factor.
14
⋅ x
/14
= 14
⋅
5
/7
Rewrite the expression.
x
=
14
⋅
5
/7
Simplify 14
⋅ 5/
7
.
Cancel the common factor of 7
.
Factor 7 out of 14
.
x
=
7
(
2
)
⋅
5/
7
Cancel the common factor.
x
=
7
⋅ 2
⋅ 5/
7
Rewrite the expression.
x =
2
⋅
5
Multiply 2 by 5
.
<u>x
=
10</u>
option 2. it increases
because as x decrease 5/x will increase which will overall increase the expression value
Answer:
The answer is 9
Step-by-step explanation:
All you need to do is divide the two numbers and you will get 9. Trust me I did this one:)
Answer:
n = 18 cycles
Step-by-step explanation:
To know how many times does the current oscillates in the given time, you take into account that the number of oscillation can be calculated by using the following expression:
(1)
f: frequency of the oscillation of the current
t: time = 0.30s
The frequency is the number of cycles per second, that is, f = 60 cycles/s
You replace the values of f and t in the equation (1):
In 0.30s the current oscillates 18 times
