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STatiana [176]
3 years ago
9

Write an equivalent expression8x - 6x + 10y + 6 + 4y + 9 = ?x + ?y + ?​

Mathematics
1 answer:
k0ka [10]3 years ago
7 0

Answer: 2x + 14y + 15

Step-by-step explanation:

8x - 6x + 10y + 6 + 4y + 9

Bring like terms together

8x - 6x  + 10y + 4y + 6 + 9

Combine like terms

2x + 14y + 15

Hope this helped!

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Consider triangle QRS. The legs each have a length of 10 units. Triangle Q R S is shown. Angle Q S R is 90 degrees. The length o
Ipatiy [6.2K]

Answer:

10 square root 2

Step-by-step explanation:

5 0
3 years ago
For brainliest please help!
Advocard [28]

Answer:

negative multiples of 3 less than -3

Step-by-step explanation:

if m <9, then

m ={8,7,6,5,4,3,2,1,0,-1,-2,....,..........}

And |6m-55|

So is said that,

when, m= 8

6(8)-55=-6

when, m=7

6(7)-54=-12

when, m = 6

6(6)-54=-18

Since the trend is negative multiples of 3 less than -3

this is my answer

8 0
3 years ago
A garden box has a perimeter of 18½ feet. If the length is 5 feet, what is the area of the garden box?
Travka [436]

Answer:

area=\frac{85}{4}feet^{2}

Step-by-step explanation:

1. Approach

Since it is given that the garden box is a rectangle, then the opposite sides are congruent. One can use this to their advantage, by setting up an equation that enables them to solve for the width of the rectangle. After doing so, one will multiply the width by the given length and solve for the area.

2. Solve for the width

It is given that the garden box is a rectangle. As per its definition, opposite sides in a rectangle are congruent. The problem gives the length and the perimeter of the rectangle, therefore, one can set up an equation and solve for the width.

perimeter=18\frac{1}{2}\\\\length=5

2(length+width)=perimeter

Substitute,

2(5+width)=18\frac{1}{2}

Conver the mixed number to an improper fraction. This can be done by multiplying the "number" part of the mixed number by the denominator of the fraction. Then add the result to the numerator.

2(5+width)=\frac{37}{2}

Inverse operations,

2(5+width)=\frac{37}{2}\\/2\\\\5+width=\frac{37}{4}\\-5\\\\width=\frac{17}{4}

3. Solve for the area

Now that one has solved for the width of the box, one must solve for the area. This can be done by multiplying the length by the width. Since the width is a fraction, one must remember, that when multiplying an integer by a fraction, one will multiply the integer by the numerator (the top of the fraction), and then simplify by reducing the fraction, if possible. Reducing the fraction is when one divides both the numerator and the denominator by the GCF (Greatest Common Factor).

length=5\\\\width = \frac{17}{4}

length*width=area

Substitute,

5*\frac{17}{4}\\\\=\frac{85}{4}

area=\frac{85}{4}feet^{2}

4 0
3 years ago
What is the right answer?? Please tell meeee
telo118 [61]

Answer:

2\sqrt{x}+\frac{1}{2\sqrt{x}}\left(2x+3\right)

Step-by-step explanation:

which is D on your phone

6 0
3 years ago
2. Name the segment parallel to the given segment. ​
TiliK225 [7]

Answer:

a) XT

c)ZS

I don't know of the b one

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