Ask question

Ask question

All categories

3 years ago

6

Diane worked 18 hours each week during the summer. She worked a total of 8 weeks and earned $9 an hour. How much money did Diane

earn during the summer?

2 answers:

Temka [501]3 years ago

6 0

9 x 18 = $162 each week.
162 x 8 = $1,296 made over the summer.

Paha777 [63]3 years ago

4 0

Diane earned $1,296 during the summer.

You might be interested in

Why does Charli fan pages hate on Addison fan pages?

noname [10]

Answer:

itss the internet wht do u expect

3 0

3 years ago

Click an item in the list of groups of pictures at the bottom of the problem and, holding the button down, drag it into the corr

tankabanditka [31]

An equation is formed of two equal expressions. The equation of the exponential graph is A=100(0.5)ˣ.

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The equation of an exponential function is given by the formula,

y = A (B)ˣ

Now as per the graph, there are two points (1, 50) and (2, 25).

50 = A (B)¹

50 = AB

A = 50/B

Substitute another point in the equation,.

25 = A (B)²

25 = (50/B) (B)²

25 = 50B

B = 0.5

Substitute the value of B,

A = 50/0.5 = 100

Hence, the equation of the exponential graph is A=100(0.5)ˣ.

Learn more about Equation:

brainly.com/question/2263981

#SPJ1

3 0

2 years ago

Twenty, which is 4 more than half, of the students in Bryan’s homeroom have tickets to attend the school’s musical. Choose Yes o

Ad libitum [116K]

Answer:

$4-\frac{1}{2}m=20$ ......No

$\frac{1}{2}m+4=20$ .......Yes

$\frac{1}{2}m-4=20$ .....No

$4=20-\frac{1}{2}m$ ......Yes

Step-by-step explanation:

Let the number of students in Byran's homeroom who have tickets to attend the school's musical be m.

Then 4 more than half this number is written as: $\frac{1}{2}m+4$

According to thee given statement, this expression is equal to 20.

$\frac{1}{2}m+4=20$

We can subtract $\frac{1}{2}m$ from both sides to create an equivalent expression.

$4=20-\frac{1}{2}m$

8 0

3 years ago

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo

muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: $P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}$

Where $\lambda$ is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

$P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}$

Substitute the respective values in the above formula.

$P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})$

$P(k > 2)= 1 - (0.44596)$

$P(k > 2)=0.55404$

Hence, the required probability is 0.55404.

4 0

3 years ago

Question 2<br>Subtracting the sum of 2.1 +23 and + 7 from –8 – 573 + 1 gives

IrinaK [193]

Answer:

1=25.1

2=-573

Step-by-step explanation:

8 0

3 years ago