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Mandarinka [93]
2 years ago
9

two children, moe and joe, are allowed to select candy from a plate of nine pieces of candy. Moe, being younger, is allowed to c

hoose first but can only take two candies. Joe is then allowed to take three of the remaining candies. Joe complains that he has fewer choices than Moe. Is joe correct? How many choices will each child have?
Mathematics
1 answer:
Ugo [173]2 years ago
3 0
Joe is correct because Moe could choose two pieces but had a nine piece variety where as Joe could only choose from 7 pieces of candy
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Pie

For this case we have by definition, that the equation of a line in the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cutoff point with the y axis

We need two points through which the line passes to find the slope:

(0, -4)\\(1,0)

We found the slope:

m = \frac {y2-y1} {x2-x1}\\m = \frac {0 - (- 4)} {1-0} = \frac {4} {1} = 4

So, the equation is of the form:

y = 4x + b

We substitute a point to find "b":

-4 = 4 (0) + b\\-4 = b

Finally, the equation is:

y = 4x-4

Answer:

Option D

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3 years ago
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RoseWind [281]
I would say A but I’m not 100% sure.
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3 years ago
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Someone please help me
Firdavs [7]

Answer:

  x = -3/2

Step-by-step explanation:

The removable discontinuity is at the value of x where a denominator factor cancels a numerator factor, and those factors are zero.

  p(x)=\dfrac{2x+3}{4x^2-9}=\dfrac{2x+3}{(2x+3)(2x-3)}=\dfrac{2x+3}{2x+3}\cdot\dfrac{1}{2x-3}\\\\p(x)=\dfrac{1}{2x-3}\qquad x\ne-3/2

That cancellation occurs where 2x+3 = 0, at x=-3/2.

The function p(x) has a removable discontinuity when x = -3/2.

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Let's start with deleting +3d and -3d (because they have opposite signs)

8d-8 = 3d

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8d-3d = 8

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5d/5 = 8/5

d = 8/5
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3 years ago
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