How does the volume of a cylinder change when its diameter is halved
1 answer:
The volume of a cylinder is given by πr²h where, r is the radius of the cylinder and <span>h </span>is the height of the cylinder.
Also<span> r=d/2</span> , where d is the diameter of the cylinder.
Therefore if the diameter is halved, the radius also gets halved ,i.e., it becomes r/2. Therefore the new volume =<span> π(r/2)²h</span>
=π(r²/4)h
<span>=(1/4) πr²h</span>
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Answer:
116*
Step-by-step explanation:
36* + 28* = 64*
180* - 64* = 116*
1/3
Hope this helps! :)
(I’m actually doing IXL too lol)
$2 is the answer I assume
Simplifying-
(6d^2)(-7d)=
= -(42d^2)(d)
=-42d^3
