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ycow [4]
3 years ago
9

What is 12 1/2% of 256

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
6 0
To determine this, we need to set up fractional proportions.
First, put 12.5% (what we're looking for) over 100%, which is the total (256).
12.5/100 should be your first fraction.
Now, put x over 256, x being 12.5% of 256.
x/256 should be your second fraction.
Now put these two fractions as an equation.
x/256 = 12.5/100
This may be where things get tricky if you don't pay attention.
Cross multiply the top number (numerator) of x/256 with the bottom number (denominator) of 12.5/100.
You should end up with 100x.
Now, cross multiply the top number of 12.5/100 with the bottom number of x/256.
You should end up with 3200.
Now our equation is:
100x = 3200
Divide both sides by 100 to get x.
100x/100 = x
3200/100 = 32
x = 32 is now your simplified equation.
Your final answer is:
32 is 12.5% of 256.
Also, since 12.5% is 1/8 of 100%, we can test our answer.
Multiply 32 by 8 to get 8/8 (100%).
32 x 8 = 256.
Your answer is 32.
I hope this helps!

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PLEASE PLEASE PLEASE HELP ME WITH ALGEBRA 1 PLEASE!?!?!?!?!!!?!?!?!?!?! I WILL GIVE LOTS OF POINTS AND BRAINLEST
Damm [24]

<span>1.1 What are the different ways you can solve a system of linear equations in two variables? 

</span><span>A linear equation can be written in many ways, so the way we can use to solve a system of linear equations depends on the form the system is written. There are several methods to do this, the more common are: Method of Equalization, Substitution Method, Elimination Method. 

<span>1.2. Method of Equalization

</span>a. Write the two equations in the style [variable = other terms] either variable x or y.<span>
</span>b. Equalize the two equations 
c. Solve for the other variable and then for the first variable.

</span>

<span> 1.3. Substitution Method

a. Write one of the equations (the one that looks the simplest equation) in the style [variable = other terms] either variable x or y.
b. Substitute that variable in the other equation and solve using the usual algebra methods.
c. Solve the other equation for the other variable.<span>

1.4. Elimination Method

Eliminate</span> means to remove, so this method works by removing variables until there is just one left. The process is:
<span>
</span>a. Multiply an equation by a constant "a" such that there is a term in one equation like [a*variable] and there is a term in the other equation like [-a*variable]
b. Add (or subtract) an equation on to another equation so the aim is to eliminate the term (a*variable)
c. Solving for one variable and the for the other.
</span>

2.1 Benefits of Method of Equalization<span>
</span>


It's useful for equations that are in the form [variable = other terms] (both equations). In this way, it is fast to solve the system of linear equation by using this method. The limitations come up as neither of the equations are written in that way, so it would be necessary to rewrite the two equations to achieve our goal


2.2. Benefits and limitations of Substitution Method


This method is useful for equations that at least one of them is in the form [variable = other terms]. So unlike the previous method, you only need one equation to be expressed in this way. Hence, it is fast to solve the system of linear equation by using this method. The limitations are the same that happens with the previous method, if neither of the equations is written in that way, we would need to rewrite one equation to achieve our goal.


2.3. Benefits and limitations of Elimination Method


It's useful for equations in which the term [a*variable] appears in one equation and the term [-a*variable] appears in the other one, so adding (or subtracting). 


3.1. What are the different types of solutions


When the number of equations is the same as the number of variables there is likely to be a solution. Not guaranteed, but likely.

One solution: It's also called a consistent system. It happens as each equation gives new information, also called Linear Independence.

An infinite number of solutions: It's also called a consistent system, but happens when the two equations are really the same, also called Linear Dependence.

No solutions: It happens when they are actually parallel lines. 


3.2. Graph of one solution system


See figure 1, so there must be two straight lines with different slopes.


3.3. Graph of infinite number of solutions system


See figure 2. So there must be two straight lines that are really the same.


3.4. Graph of no solution system


See figure 3. So there must be two straight lines that are parallel.


4. Explain how using systems of equations might help you find a better deal on renting a car?


Q. A rental car agency charges $30 per day plus 10 cents per mile to rent a certain car. Another agency charges $20 per day plus 15 cents per mile to rent the same car. If the car is rented for one day in how many miles will the charge from both agencies be equal?

A. Recall: 10 cents = 0.1$, 15 cents = 0.15$

If you rent a car from the first car agency your cost for the rental will be:

(1) 30D+0.1M

<span>If you rent a car from the second car agency the total amount of money to pay is:

(2) 20D+0.15M</span>

Given that the problem says you want to rent the car just for one day, then D = 1, therefore:

First agency: 30(1)+0.1M=&#10;\boxed{30+0.1M}

Second agency: 20(1)+0.15M=&#10;\boxed{20+0.15M}

<span>At some number of miles driven the two costs will be the same:

30+0.1M=20+0.15M

Solving for M:

10=0.05M
M=200mi

There is a representation of this problem in figure 4. Up until you drive 200 miles you would save money by going with the second company.</span>

<span>

5. Describe different situations in the real world that could be modeled and solved by a system of equations in two variables </span>

<span>
</span>

For example, if you want to choose between two phone plans. The plan with the first company costs a certain price per month with calls costing an additional charge in cents per minute. The second company offers another plan at a certain price per month with calls costing an additional charge in cents per minute. So depending on the minutes used you should one or another plan.


3 0
3 years ago
Which linear function represents the line given by the point-slope equation y-8=
Nina [5.8K]

Answer:

f(x)=x+4

Step-by-step explanation:

we have

y-8=(x-4)

This is the equation of the line in point slope form

where

The slope is m=1

The point is (4,8)

Convert to slope intercept form

Isolate the variable y

Adds 8 both sides

y-8+8=x-4+8

Combine like terms

y=x+4

Convert to function notation

f(x)=x+4

5 0
3 years ago
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Klio2033 [76]
The human ran 0.45 miles per minute.

27 divided by 60 = 0.45

The 60 is the number of seconds in a minute.

Hope this helped! :)
6 0
3 years ago
Anyone can help me I would appreciate it
Kisachek [45]

Answer:

This would be shifted down 8 and made 3 times less steep.

Step-by-step explanation:

In order to determine these transformations, we first need to compare the constants at the end. This will determine the up or downward shift. Since the f(x) is 5 and the g(x) is -3, we know that it went down 8.

Next we compare the coefficients of x. Since the f(x) is 6 and the g(x) is 2, we know that it is 3 times less steep.

7 0
3 years ago
Which reason justifies the last step in a proof that ∆DEF ≅ ∆DAB?
lesya [120]
Hey there, Sheriawilright!

The correct answer should be C since we are given two sides AD is congruent to ED and D is the midpoint of Line BF meaning that BD and BF are the same. Also, it makes both lines make a vertical angle meaning they are the same. So we have two sides and an angle between, so the answer is Side Angle Side.

Thank you for using Brainly.
See you soon!
7 0
3 years ago
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