Answer:
The radical notation is ![3x\sqrt[3]{y^2z}](https://tex.z-dn.net/?f=3x%5Csqrt%5B3%5D%7By%5E2z%7D)
Step-by-step explanation:
Given
![\sqrt[3]{27 x^{3} y^{2} z}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%20x%5E%7B3%7D%20y%5E%7B2%7D%20z%7D)
Step 1 of 1
Write the expression using rational exponents.
![\sqrt[n]{a^{m}}=\left(a^{m}\right)^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%7D%3D%5Cleft%28a%5E%7Bm%7D%5Cright%29%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)





Simplify 
![$=3 x \sqrt[3]{y^{2} z}$](https://tex.z-dn.net/?f=%24%3D3%20x%20%5Csqrt%5B3%5D%7By%5E%7B2%7D%20z%7D%24)
Learn more about radical notation, refer :
brainly.com/question/15678734
Answer: fourth option
Explanation:1) the pair x = 3 f(x) = 0, leads you to probe this:
f(3) = 0 = A [4 ^ (3 - 1) ] + C = 0
=> A [4^2] = - C
A[16] = - C
if A = 1/4
16 / 4 = 4 => C = - 4
That leads you to the function f(x) = [1/4] 4 ^( x - 1) - 4
2) Now you verify the images for that function for all the x-values of the table:
x = 2 => f(2) + [1/4] 4 ^ (2 - 1) - 4 = [1/4] 4 - 4 = 4 / 4 - 4 = 1 - 4 = - 3 => check
x = 3 => f(3) = [1/4] 4^ (3 - 1) - 4 = [1/4] 4^2 - 4 = 16 / 4 - 4 = 4 - 4 = 0 => check
x = 4 -> f(4) = [1/4] 4^ (4-1) - 4 = [1/4] 4^(3) - 4 = (4^3) / 4 - 4 = 4^2 - 4 = 16 - 4 = 12 => check.
Therefore, you have proved that the answer is the fourth option.
C = 9/28 = 0.321
https://www.tiger-algebra.com/drill/3c-3/4=2c/3/
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