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3 years ago

What is the correlation coefficient for the data shown in the table?

Mathematics

1 answer:

Butoxors [25]3 years ago

3 0

Coefficient is a number that has a letter next to it. None of have it

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Geri believed the answer to one of her homework problems was 2 cubed. After checking her work, she realized the correct answer w

Murrr4er [49]

Answer:

Step-by-step explanation:

7 0

3 years ago

Degger [83]

Answer: True

---------------------------------

Work Shown:

Follow PEMDAS in reverse to solve for q
22q - 7 < 37
22q - 7+7 < 37+7 ... add 7 to both sides
22q < 44
22q/22 < 44/22 ... divide both sides by 22
q < 2

7 0

3 years ago

What is the image of (1,0) after a counterclockwise rotation of 60 degrees?

Anestetic [448]

Answer:

$\vec s = \left(\frac{1}{2},\frac{\sqrt{3}}{2} \right)$

Step-by-step explanation:

The coordinate has the following polar form:

$\vec r = (1, 0^{\circ})$

The image of the coordinate rotated counterclockwise 60° is:

$\vec s = (1, 60^{\circ})$

Its equivalent form in rectangular coordinates is:

$\vec s = (1\cdot \cos 60^{\circ}, 1 \cdot \sin 60^{\circ})$

$\vec s = \left(\frac{1}{2},\frac{\sqrt{3}}{2} \right)$

3 0

3 years ago

Can someone please do this for me?

san4es73 [151]

Answer:

64°

Step-by-step explanation:

So supplement angles are equal to 180, so first our two angles added together will be 180:

x + x = 180

Now one of these angles is 6 greater than half:

x + (x/2 + 6) = 180

Then we will solve for x:

x + (x/2 + 6) = 180

x + x/2 + 6 = 180

x + x/2 = 174

$\frac{3}{2}$ x = 174

x = 116

Plug it back in:

x + (x/2 + 6) = 180

x/2 + 6

(116)/2 + 6

To check:

116 + 64 = 180 ✓

6 0

3 years ago

A village fete has a children’s running race each year, run in heats of up to ten children. For each heat the first three contes

bekas [8.4K]

Answer: 1) 1/3,654 2) 3/406 3) 72,684,900,288,000 4) 120

Step-by-step explanation:

1) First and Second and Third

$\dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}\times \dfrac{1\ remaining\ prize}{27\ remaining\ people}=\dfrac{6}{21,924}\\\\\\.\qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \quad =\large\boxed{\dfrac{1}{3,654}}$

2) First and Second

$\dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}=\dfrac{6}{812}=\large\boxed{\dfrac{13}{406}}$

$3)\quad \dfrac{29!}{(29-10)!}=\large\boxed{72,684,900,288,000}$

$4)\quad _{10}C_3=\dfrac{10!}{3!(10-3)!}=\large\boxed{120}$

8 0

3 years ago