Is x3 an exponent ? i answered one of ur earlier questions and i assumed x3 was multiplication
9 + (7 - 1)^3
= 9 + (6)^3
= 9 + (216)
= 225
or if it is multiplication...
then the answer is 27
Answer:
a) one solution(x = 9)
b) no solution
c) infinite solutions
Step-by-step explanation:
a) To solve this equation, we can add 4 on both sides in order to isolate x:
x - 4 =5
+ 4 + 4
x = 9
Since x equals 9, that counts as only one solution, as there is only one value of x that makes the equation true.
b) We start by subtracting 2x from both sides to combine the variable terms:
2x - 6 = 2x + 5
-2x -2x
-6 = 5
The statement, -6 = 5 is never true and it is not dependent on the value of x. This means there are no solutions to this equation.
c) We can start by subtracting 3x from both sides to combine the terms with x:
3x + 12 = 3x + 12
-3x -3x
12 = 12
The statement above is always true, and no matter the value of x, it will always be true. This means there are infinite solutions to the equation.
I'm assuming that x is part of the data set, and, with x, the mean equals 105. To find the value of x, you must add all the data values together to get 544+x (you still don't know what x equals). Then put 544+x over how many days values there are, including x (there are 6). You should have 544+x/6. Now, as this is how you would calculate the mean if you knew what x was equal to, you must set it equal to the mean, since you know what it is (105). You should now have 544+x/6 = 105. You have your equation set up--now you just have to solve it. I would multiply by 6 on both sides to get rid of the 6 on the left side. You would then have 544+x = 630. I would finally subtract 544 from both sides to get x = 86. Your final answer is x = 86.
