Answer:
The minimum score required for recruitment is 668.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Top 4%
A university plans to recruit students whose scores are in the top 4%. What is the minimum score required for recruitment?
Value of X when Z has a pvalue of 1-0.04 = 0.96. So it is X when Z = 1.75.




Rounded to the nearest whole number, 668
The minimum score required for recruitment is 668.
Answer:
27x^3 - 54x^2 + 36x - 8
Step-by-step explanation:
(3x - 2)^3
= (3x - 2) (3x - 2) (3x - 2)
= 27x^3 - 54x^2 + 36x - 8
Hope this helps :)
Let me know if there are any mistakes!!
Answer:
f(g(2)) = 44
Step-by-step explanation:
g(2) = 3(2) + 1 = 7
Plug 7 into f(x) since g(2) = 7
f(7) = 7² - 5 = 44
f(g(2)) = 44
Answer:
-0.08
Step-by-step explanation:
Multiply.
-0.2
x 0.4
_____
0 0 8
Each number you started out with has 1 space between the last number and the decimal, so your final answer will have 2 spaces.
Also, since you multiplied a negative and a positive, your final answer will be negative.
2w+2(5+2w)=33
2w+10+4w=33
6w=22
w=11/3 or 3 and 2/3