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Igoryamba
3 years ago
3

A skateboard halfpipe is being designed for a competition. The halfpipe will be in the shape of a parabola and will be positione

d above the ground such that its focus is 40 ft above the ground. Using the ground as the x-axis, where should the base of the halfpipe be positioned? Which equation best describes the equation of the halfpipe? (0, 20); y equals one over eighty times x squared plus 20 (0, 10); y equals one over one hundred twenty times x squared plus 10 (0, 20); y equals one over eighty times x squared minus 20 (0, 10); y equals one over one hundred twenty times x squared minus 10

Mathematics
1 answer:
Dahasolnce [82]3 years ago
4 0

Answer:

The EQUATION : y = \frac{x^{2} }{80} + 20

Step-by-step explanation:

Attached below is the solution to determine the required equation tha best describes the equation of the half pipe

hence the base of the pipeline should be positioned as

will be as represented in the equation : \frac{x^{2} }{80} + 20

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Step-by-step explanation:

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Triangle ABC has vertices at A(3, 8) , B(11, 8) , and C(7, 12) . Triangle FGH has vertices at F(8, 4) , G(16, 4) , and H(12, 8)
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Vertices of ΔABC 
A - <span>(3, 8)
</span><span>B - (11, 8)
C - (7, 12)
vertices  of </span>Δ<span>FGH
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G - (16, 4)
H - (12, 8) 
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if we take point A and F
x coordinates of A = 3 and F = 8
the change that has happened can be noted as 'm'
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m = 5
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change that happened is 'n'
8 + n = 4
n = -4
this means that point has moved 4 units downwards

Therefore the correct answer is </span><span>Translate ​ triangle ABC ​ down 4 units, and then translate ​ triangle ABC right 5 units</span>
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4 years ago
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−<span>2.8
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