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3241004551 [841]

4 years ago

11

Persevere in Problem Solving Find a sequence of three transformations that can be used to obtain figure D from figure A. Graph t

he figures B and C that are created by the transformations.

2 answers:

ahrayia [7]4 years ago

8 0

The Answer would be b

Irina-Kira [14]4 years ago

7 0

Answer:

graph the figures B

Step-by-step explanation:

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Jo is thinking of a number. four less than 9 times the number is 176. find jo's number

luda_lava [24]

Answer:20

Step-by-step explanation:

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3 years ago

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The area is (2x + 15) square centimeters.

emmainna [20.7K]

Answer:

$Area\:shaded=\frac{3}{5} (2x+15)$

Step-by-step explanation:

Let $s$ be the shaded area and $u$ be the unshaded area, then we know that

(1). $\frac{s}{u}=\frac{3}{2}$

and

(2). $s+u=(2x+15)$

We solve for $u$ in the first equation and get:

$u=\frac{2}{3}s$

and put this into the second equation and get:

$s+\frac{2}{3}s=(2x+15)$

$s(1+\frac{2}{3} )=(2x+15)$

$s(\frac{5}{3} )=(2x+15)$

$\boxed{s=\frac{3}{5} (2x+15)}$

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3 years ago

What is the first step of the problem solving strategy

beks73 [17]

understanding the problem

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4 years ago

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Which is the equation of the graphed line written in standard form?

Rudiy27

Whats the equation...............

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3 years ago

WILL GIVE BRAINLIEST

IrinaK [193]

Part one:

$x^2-8x=-26$

Rewrite in the form $(x+a)^{2} =b$

$\left(x-4\right)^2=-10$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

Solve $x-4=\sqrt{-10} : x=\sqrt{10} i+4$

Solve $x-4=\sqrt{-10} : x=-\sqrt{10} i+4$

$x=\sqrt{10}i+4,\:x=-\sqrt{10}i+4$

Part two:

$x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:26}}{2\cdot \:1}$

Simplify $\sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:26}}: 2\sqrt{10} i$

$=\frac{-\left(-8\right)\pm \:2\sqrt{10}i}{2\cdot \:1}$

Separate solutions

$x_1=\frac{-\left(-8\right)+2\sqrt{10}i}{2\cdot \:1},\:x_2=\frac{-\left(-8\right)-2\sqrt{10}i}{2\cdot \:1}$

$\frac{-(-8)+2\sqrt{10}i }{2*1} :4+\sqrt{10}i$

$\frac{-(-8)+2\sqrt{10}i }{2*1} :4-\sqrt{10}i$

$x=4+\sqrt{10}i,\:x=4-\sqrt{10}i$

7 0

3 years ago