All categories

3 years ago

(1/4) raised to the 3z-1 = 16 raised to the z+2 multiplied by 64 raised to the z-2

Mathematics

1 answer:

meriva3 years ago

6 0

:) Brainliest pls?

Answer:

z = 3/8

Step-by-step explanation:

(1/4)^(3z-1) = (64^(z-2)) * (16^(z+2))

The work is too much. I don't have a camera to take a photo of the paper.

z = 3/8

You might be interested in

A company puts bottles of lotions into boxes that are 3 inch cubes. The boxes were then backed into a shipping crate that is a 2

Sonbull [250]

1 foot = 12 inches, so now you add 3 inches until you get 12. you add 3, 4 times toget 12. 3+3=6+3=9+3=12 and do that again for the 2nd foot 3+3=6+3=9+3=12 you added 3, 4 times to get 12 twice so now add 4+4=8
YOUR ANSWER IS 8

8 0

3 years ago

Find the length of the third side. If necessary, write in simplest radical form. 9 5

tigry1 [53]

Step-by-step explanation:

$(9) {}^{2} = (5) {}^{2} + (x) {}^{2} \\ 81 = 25 + {x}^{2} \\ {x}^{2} = 56 \\ x = 2 \sqrt{14} = 7.4$

7 0

3 years ago

Teresa Gonzalez and Alan Carillo spent a total of $215.75 on their prom

agasfer [191]

Answer:$139.88

Step-by-step explanation:

215,75-75.87 is 139.88

4 0

3 years ago

If (3 , K) and (2, 4k) are two points on a graph of a line and k is not equal to 0, what is the slope of the line?

agasfer [191]

I honestly don’t know, Try to do Y2-Y1 and X2-X1 to get your answer.

7 0

3 years ago

Mr. Harris is packaging items to give to his students. He has 48 pencils and 30 notebooks. He wants each package to contain the

guapka [62]

Answer:

The maximum number of packages that can be made with each package have same number of each item is = 6

Step-by-step explanation:

Given:

Mr. Harris has 48 pencils and 30 notebooks.

To find the number of packages he can make with each package have same number of each item.

Solution:

Number of pencils = 48

Number of notebooks = 30

In order to find the number of packages he can make with each package have same number of each item, we will find the greatest common factor of the given numbers.

<em>To find the G.C.F., we will list down the prime factors of each.</em>

$48=2\times 2\times 2\times 2\times 3$

$30=2\times 3\times 5$

We find that the G.C.F. = $2\times 3$ = 6

Thus, the maximum number of packages that can be made with each package have same number of each item is = 6

4 0

3 years ago