1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nignag [31]
3 years ago
6

Find the excluded value of the function Y= - 10/6x-5. The excluded value is x =??

Mathematics
1 answer:
Masteriza [31]3 years ago
8 0

Answer:

The excluded value is x = 5/6

Step-by-step explanation:

Here, we want to calculate the excluded value

The excluded value is simply the value of x that will make the denominator of the fraction equals zero

We have this as;

6x -5 = 0

6x = 5

x = 5/6

You might be interested in
.........................................
xeze [42]

Answer:

yes

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A caterpillar eats 1400\%1400%1400, percent of its birth mass in one day. The caterpillar's birth mass is mmm grams.
makvit [3.9K]

Answer:

I d k

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Miranda enlarged a picture twice as shown below, each time using a scale factor of 3.
lyudmila [28]

Answer:

The area of the second enlargement is 1,944 square inches

The area of the second enlargement is (3 squared) squared times the original area.

The ratio of the area of the first enlargement to the area of the original equals the square of the scale factor

Step-by-step explanation:

<u><em>Verify each statement</em></u>

1) The area of the first enlargement is 72 square inches.

The statement is false

Because

we know that

The original dimensions of the rectangle are

length 6 inches and width 4 inches

so

First enlargement

Multiply the original dimensions by a scale factor of 3

Length: 6(3)=18\ inches\\Width: 4(3)=12\ inches

The area of the first enlargement is

18(12)=216\ in^2

2) The area of the second enlargement is 1,944 square inches

The statement is true

Multiply the dimensions of the first enlargement by a scale factor of 3

Length: 18(3)=54\ inches\\Width: 12(3)=36\ inches

The area of the second enlargement is

54(36)=1,944\ in^2

3) The area of the second enlargement is (3 squared) squared times the original area.

The statement is true

Because

The original area is 24 square inches

[(3^2)]^2(24)=1,944\ in^2

4) The area of the second enlargement is 3 times the area of the first enlargement

The statement is false

Because

3(216)=648\ in^2

so

648\ in^2 \neq 1,944\ in^2

5) The ratio of the area of the first enlargement to the area of the original equals the square of the scale factor

The statement is true

Because

The square of the scale factor is 3^2=9

and the ratio is equal to

\frac{216}{24}=9

8 0
3 years ago
Read 2 more answers
4(x + 3) = 6-x what is the answer I need help please
Amanda [17]
4(x + 3) = 6 - x

First, expand to remove parentheses.
4x + 12 = 6 - x
Second, subtract '6' from both sides.
4x + 12 - 6 = -x
Third, subtract '12 - 6' to get 6.
4x + 6 = -x
Fourth, subtract '4x' from both sides.
6 = -x - 4x
Fifth, since 'x' can be referred to as '1', add it to '4x' to get '-5x'.
6 = -5x
Sixth, divide both sides by '-5'.
\frac{6}{-5} =x
Seventh, change the whole fraction into a negative.
-\frac{6}{5} =x
Eighth, switch your sides.
x =  -\frac{6}{5}

Answer as fraction: -\frac{6}{5}
Answer as decimal: -1.2

4 0
3 years ago
Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)
GarryVolchara [31]

<u>Question 6</u>

1) \overline{AB} \cong \overline{BD}, \overline{CD} \perp \overline{BD}, O is the midpoint of \overline{BD}, \overline{AB} \cong \overline{CD} (given)

2) \angle ABO, \angle ODC are right angles (perpendicular lines form right angles)

3) \triangle ABO, \triangle CDO are right triangles (a triangle with a right angle is a right triangle)

4) \overline{BO} \cong \overline{OD} (a midpoint splits a segment into two congruent parts)

5) \triangle ABO \cong \triangle CDO (LL)

<u>Question 7</u>

1) \angle ADC, \angle BDC are right angles), \overline{AD} \cong \overline{BD}

2) \overline{CD} \cong \overline{CD} (reflexive property)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \triangle ADC \cong \triangle BDC (LL)

5) \overline{AC} \cong \overline{BC} (CPCTC)

<u>Question 8</u>

1) \overline{CD} \perp \overline{AB}, point D bisects \overline{AB} (given)

2) \angle CDA, \angle CDB are right angles (perpendicular lines form right angles)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \overline{AD} \cong \overline{DB} (definition of a bisector)

5) \overline{CD} \cong \overline{CD} (reflexive property)

6)  \triangle ADC \cong \triangle BDC (LL)

7) \angle ACD \cong \angle BCD (CPCTC)

8 0
2 years ago
Other questions:
  • Find c1 and c2 such that M2+c1M+c2I2=0, where I2 is the identity 2×2 matrix and 0 is the zero matrix of appropriate dimension.
    8·1 answer
  • 39,189 rounded to nearest thousand
    14·1 answer
  • What is the slope of a line perpendicular to the line with the equation y = 6 x + 2
    9·1 answer
  • Factor completely.<br> 2x2 - 18x + 36 =<br> Stuck? Use a hint.<br> Rep<br> 3
    5·1 answer
  • A basketball has a diameter of 9.5 cm. Which of the expressions shows how to determine the volume of air the basketball can hold
    6·1 answer
  • Solve for x. Write the smaller solution first, and the larger solution second.
    13·1 answer
  • ABCD is a trapezoid. segment AB = 1 cm and segment CD = 5 cm, and the area = 7.5 cm2. What is the altitude of the trapezoid?
    15·2 answers
  • OOP I NEED HELP I STUPID EDO
    7·2 answers
  • PLZ GUYS THIS IS REALLY HARD
    14·2 answers
  • Solve 3x + 5 = 2x + 7
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!