The solutions are where the quadratic is equal to 0, or when the quadratic crosses the x axis.
Where the quadratic crosses the x axis are the solutions:
6) x = –5, x = –6
7) x = 0, x = 1
8) x = –6, x = 1
9) x = –4, x = –3
Make sure that you are looking at the right boxes
30 = arc BC / 2
arc BC = 2(30)
arc BC = 60
answer
D. 60
Answer:
x^2+3=h
to make x the subject of the formula,move 3 to the other side making it negative
x^2 = h + 3
to take out the square,take the square root of both sides.
√x^2 = √ h + 3
x = √ h + 3.
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Answer: y = 4x + 1
Step-by-step explanation:
1. Make the equation its parallel to in slope intercept form by subtacting 4x to get -y = -4x+ 2 then dividing both sides by -1 to get y = 4x -2
When dealing with parallel lines thier slopes are ALWAYS the same, so the equation we are making should have the slope of 4.
2. Plug in the corrordinates x and y values and the slope into the point-slope form equation to find the y intercept
(y - (-3)) = 4(x - (-1))
3. Solve for y in slope intercept form:
y + 3 = 4x + 4 ----> y = 4x + 1
