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Sunny_sXe [5.5K]
3 years ago
12

What is the length of MQ?

Mathematics
1 answer:
uranmaximum [27]3 years ago
6 0

Answer:

In general, IBM MQ object names can be up to 48 characters long

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What’s the slope ? I don’t understand
jarptica [38.1K]

Answer: Slope is rise over run, or y over x. So for the first one the slope is 60/30 or 2. If you wanna find the slope between two points you would do y2-y1 over x2-x1. For example if we use the first two points which are 60/30 and 50/40, it would be 50-60 over 40-30, which gives you -10/10. That can be simplified down to -1/1. That means that you have went down one and right one on your graph. You can apply these rules to many basic slope problems. I hope this helps! :)

6 0
3 years ago
Please help me with the question below and i will mark you as BRAINLIEST
d1i1m1o1n [39]

Answer:

28.8

Step-by-step explanation:

Hope this helps!!!

7 0
3 years ago
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Liam has 2 quarts of apple juice. He wants to pour the juice into 1/5-quarts servings. How many servings can he pour?
nydimaria [60]

Answer:

10 servings

Step-by-step explanation:

Divide the total juice available, 2 quarts, by the serving size, (1/5) quart per serving:

 2 quarts                     2        5

--------------------------- = ----  ·  ------ servings = 10 servings

(1/5) quart/serving       1         1

6 0
3 years ago
If the function h is defined by h(x)=<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" a
harkovskaia [24]

Given:

The function is:

h(x)=x^2-3x+5

To find:

The value of h(2x+1).

Solution:

We have,

h(x)=x^2-3x+5

Putting x=2x+1, we get

h(2x+1)=(2x+1)^2-3(2x+1)+5

h(2x+1)=(2x)^2+2(2x)(1)+(1)^2-3(2x)-3(1)+5

h(2x+1)=4x^2+4x+1-6x-3+5

On combining like terms, we get

h(2x+1)=4x^2+(4x-6x)+(1-3+5)

h(2x+1)=4x^2-2x+3

Therefore, the required function is h(2x+1)=4x^2-2x+3.

3 0
3 years ago
2+8<br><br> PLSSS HELP PLSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS
romanna [79]

Answer:

10

Step-by-step explanation

2 + 8= 10

6 0
3 years ago
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