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Vadim26 [7]
3 years ago
5

Jan's age is 3 years less than twice Tritts age.The sum of their ages is 30. Find their ages

Mathematics
1 answer:
Zanzabum3 years ago
5 0
Jan age is 19. Tritt age is 11.
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10. If 9! is 362880, find 10!.
allochka39001 [22]

Answer:

  3628800

Step-by-step explanation:

10! = 10 × 9! = 10 × 362880

  = 3628800

_____

A number is multiplied by 10 by shifting the decimal point one place to the right. Here, that means appending a place-holder zero to the number.

4 0
3 years ago
Find the equation of a line that passes through the given points<br>(-6,-5) and (6,-13)
NeTakaya

Answer:

y+5=-3/4(x+6)

or in slope intercept

y= -3/4x-38/4

Step-by-step explanation:

To write the equation of a line we must have a slope and a point. To find the slope we use the slope formula and substitute (x,y) points in it as shown below:

m=\frac{y_2-y_1}{x_2-x_1}=\frac{-5--13}{-6-6}=\frac{-5+13}{-6+-6}=\frac{8}{-12}=\frac{-3}{4}

Now that we have the slope, plug in the slope and choose one point to plug into the point slope formula. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.

(y--5)=-3/4(x--6)

y+5=-3/4(x+6)

y+5=-3/4x-18/4

y=-3/4x-18/4-20/4

y= -3/4x-38/4



5 0
3 years ago
Read 2 more answers
C = ?<br>Be sure to evaluate the square root​
Butoxors [25]

Hope this will help u .

If my ans was helpful, u can follow me.

4 0
3 years ago
Simplify without using the calculator or the sin tables.​
katovenus [111]

Answer:

1/8

Step-by-step explanation:

sin²(π/8) − cos⁴(3π/8)

Use power reduction formulas:

1/2 (1 − cos(2×π/8)) − 1/8 (3 + 4 cos(2×3π/8) + cos(4×3π/8))

Simplify:

1/2 (1 − cos(π/4)) − 1/8 (3 + 4 cos(3π/4) + cos(3π/2))

1/2 (1 − √2/2) − 1/8 (3 + 4 (-√2/2) + 0)

1/2 − √2/4 − 1/8 (3 − 2√2)

1/2 − √2/4 − 3/8 +√2/4

1/2 − 3/8

1/8

7 0
3 years ago
Find the logarithmic function y = logbx that passes through the points
katovenus [111]

b\in(0,\ 1)\ \cup\ (1,\ \infty)\\x > 0\\y\in\mathbb{R}\\--------------------------\\\\y=\log_bx\\\\For\ (1,\ 0)\to x=1,\ y=0.\ Substitute:\\\\\log_b1=0\to b^0=1\to b\in(0,\ 1)\ \cup\ (1,\ \infty)\\\\For\ (116,\ 2)\to x=116,\ y=2.\ Substitute:\\\\\log_b116=2\to b^2=116\to b=\sqrt{116}\\\to b=\sqrt{4\cdot29}\to b=\sqrt4\cdot\sqrt{29}\to b=2\sqrt{29}\\\\For\ (4,\ -1)\to x=4,\ y=-1.\ Substitute:\\\\\log_b4=-1\to b^{-1}=4\to b=\dfrac{1}{4}

Different values of b.

<h3>Answer: There is no logarithmic function whose graph goes through given points.</h3><h3 />

Maybe the second point is \left(\dfrac{1}{16},\ 2\right)

Substitute:

\log_b\dfrac{1}{16}=2\to b^2=\dfrac{1}{16}\to b=\sqrt{\dfrac{1}{16}}\to b=\dfrac{1}{4}

<h3>Then we have the answer:</h3>

\boxed{y=\log_{\frac{1}{4}}x}

6 0
3 years ago
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