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vladimir2022 [97]
3 years ago
6

It is given that parallelogram JKLM is a rectangle and by the definition of a rectangle, ∠JML and ∠KLM are right angles. ∠JML≅∠K

LM because . JM⎯⎯⎯⎯⎯≅KL⎯⎯⎯⎯⎯ because , and ML⎯⎯⎯⎯⎯⎯≅ML⎯⎯⎯⎯⎯⎯ by the reflexive property of congruence. By the , △JML≅△KLM . Because , JL⎯⎯⎯⎯≅MK⎯⎯⎯⎯⎯⎯ .

Mathematics
2 answers:
Andru [333]3 years ago
8 0

Answer:  

  • all right angles are congruent.
  • opposite sides of a parallelogram are congruent
  • SAS congruence postulate
  • corresponding parts of congruent triangles are congruent

Step-by-step explanation:

Given : Parallelogram JKLM  is a rectangle and by the definition of rectangle, \angle{JML}=\text{ and }\angle{KLM} are right angles,

Since all interior angles of rectangle are right angle.

then \Rightarrow\angle{JML}\cong\angle{KLM}, because all right angles are congruent.

Also, opposite sides of a parallelogram are congruent.

\overline{JM}\cong\overline{KL}

and \overline{ML}\cong\overline{ML} by the reflexive property of congruence.

Now, by the SAS congruence postulate,

\triangle{JML}\cong\triangl{KLM},

Since corresponding parts of congruent triangles are congruent, ∴

\overline{JL}\cong\overline{MK}

  • The SAS postulate says that if two sides and the included angle of a triangle are congruent to two sides and the included angle of another triangle then the two triangles are congruent.

densk [106]3 years ago
4 0

Answer:


Step-by-step explanation:

It is given that the parallelogram JKLM  is a rectangle and by the definition of rectangle, ∠JML and ∠KLM are right angles, ∠JML ≅∠KLM because all right angles are congruent.

\overline{JM}≅\overline{KL} because opposite sides of a parallelogram are congruent, and \overline{ML}≅\overline{ML} by the reflexive property of congruence. By the SAS congruence postulate, ΔJML≅ΔKLM, because corresponding parts of congruent triangles are congruent, \overline{JL}≅\overline{MK}.

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