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ValentinkaMS [17]
3 years ago
9

Can Anyone help w/ steps? Thanks!​

Mathematics
2 answers:
Simora [160]3 years ago
6 0

\bf \sqrt[3]{-\cfrac{125}{729}}~~ \begin{cases} 125=&5\cdot 5\cdot 5\\ &5^3\\ 729=&9\cdot 9\cdot 9\\ &9^3 \end{cases}\implies \sqrt[3]{-\cfrac{5^3}{9^3}}\implies \sqrt[3]{(-1)^3\cdot \cfrac{5^3}{9^3}}\implies -\cfrac{5}{9}

patriot [66]3 years ago
4 0
I hope this could help

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Solve for x:
Dafna11 [192]

Step-by-step explanation:

5*(4x+8)=6*(2x+3)

20x+40=12x+18

20x _12x= 18_40

8x = _22

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Raquel and Van live in two different cities. As part of a project, they each record the lowest prices for a gallon of gas at gas
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Answer:

Step-by-step explanation:

Looking at the information given, the average or mean lowest prices and standard deviations for the two cities are given. The standard deviation is a measure of variability. It is used to determine how far the values in the data are from the mean. A lower standard deviation means that the values are closer to the mean. A higher standard deviation means that the values are farther from the mean.

Since 0.07 is lower than 0.23, the correct statement that is true about their gas-price data is

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3 0
2 years ago
Read 2 more answers
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dusya [7]

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Please help! How on earth do I do this? In the year 2015, Anna bought a new car for $36,000. In 2017, she was told that the valu
Klio2033 [76]

Part A

Purchase Value of Anna's Car in 2015 = $36,000

Depreciated Value of Anna's Car in 2017 = $25,000

We know that the value of the car is depreciating linearly.


From the above data, we can see that the value of the car has reduced by $36,000-$25,000 = $11,000 over 2 years.

⇒ Per year the value has been depreciated by \frac{11000}{2}

⇒ Per year the value has been depreciated by $5,500

So if the value of a car in 2015 is V₀ then value of the car after t years can be determined by the below function:

V (t) = V₀ - (t*5,500), where t indicates the years passed since 2015

OR V (t) = 36,000 - (t*5,500), where t indicates the years passed since 2015

Part B

Suggested value of Anna's car for trade in option in 2018 = $15,000

In 2018, 3 years would have been passed since 2015. Using the value of t = 3 in the function determined in Part A:

V(3) = V₀ - (3*5,500)

⇒ V(3) = 36,000 - (16,500)

⇒ V(3) = $19,000

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3 0
2 years ago
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