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Snezhnost [94]
3 years ago
14

Angus decided to invest $10,000 into a savings account. If this account earns 2.6% annually, how much money would Angus have ear

ned after 12 years?
Mathematics
2 answers:
ASHA 777 [7]3 years ago
7 0
Total = Principal * (1 + rate) ^ years
Total = 10,000.00 * 1.026^12
Total = <span> <span> <span> 13,607.186251 </span>
Total = </span></span><span>13,607.19 (rounded)
</span> 

Zielflug [23.3K]3 years ago
7 0
Angus earned 3607.19 because the question is asked for interest earned
I=13,607.19-10000=3607.19
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Constant rates are used to illustrate linear functions.

  • The average rate of change is $9.0 per hour
  • The function that models the table is: \mathbf{f(x) = 9x }
  • The amount earned in 7.5 hours is $67.5

<u>(a) The average rate of change</u>

This is calculated using:

\mathbf{Rate = \frac{y_2 -y_1}{x_2 -x_1}}

So, we have:

\mathbf{Rate = \frac{31.5-22.50}{3.5 - 2.5}}

\mathbf{Rate = \frac{9}{1.0}}

\mathbf{Rate = 9.0}

Hence, the average rate of change is $9.0 per hour

<u>(b) A function that models the table of values</u>

Let x represent hours, and y represent the earnings.

So, we have:

\mathbf{y =m (x - x_1) + y_1}

Where:

m =Rate = 9.0

So, we have:

\mathbf{y = 9(x - 2.5) + 22.5}

Expand

\mathbf{y = 9x - 22.5 + 22.5}

\mathbf{y = 9x }

Represent as a function

\mathbf{f(x) = 9x }

Hence, the function that models the table is: \mathbf{f(x) = 9x }

<u>(c) Amount earned for 7.5 hours</u>

This means that x = 7.5

So, we have:

\mathbf{f(7.5) = 9 \times 7.5 }

\mathbf{f(7.5) = 67.5}

Hence, the amount earned in 7.5 hours is $67.5

Read more about constant rates at:

brainly.com/question/23184115

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