Correct Answer: - 550
We can use the distributive property to distribute the summation to the variables and then get the constant out to apply the summation formulas as shown below in the attached image.
The equation editor does not have a summation symbol, so I have attached the solution using the image.
The correct answer to this question is -550. First option is the correct one.
Answer:
first
Step-by-step explanation:
Let us make a list of all the details we have
We are given
The cost of each solid chocolate truffle = s
The cost of each cream centre chocolate truffle = c
The cos to each chocolate truffle with nuts = n
The first type of sweet box that contains 5 each of the three types of chocolate truffle costs $41.25
That is 5s+5c+5n = 41.25 (cost of each type of truffle multiplied by their respective costs and all added together)
The second type of sweet box that contains 10 solid chocolate trufles, 5 cream centre truffles and 10 chocolate truffles with nuts cost $68.75
That is 10s+5c+10n = $68.75
The third type of sweet box that contains 24 truffles evenly divided that is 12 each of solid chocolate truffle and chocolate truffle with nuts cost $66.00
That is 12s+12n=$66.00
Hence option C is the right set of equations that will help us solve the values of each chocolate truffle.
Answer:
Step-by-step explanation:
f(x)=-4x+2
g(x)=x²+1
(gof)(x)=g(f(x))=g(-4x+2)=(-4x+2)²+2=16x²-16x+4+2=16x²-16x+6
(gof)(3)=16(3)²-16(3)+6=144-48+6=150-48=102
Answer: green = 25/100, red = 1/100
Step-by-step explanation: add ALL of the gumballs, there's your denominator, now you have 0/100 (1+74+25), count the amount of marbles you want to get the probability of, lets say green, there's your numerator (25) = 25/100
