(1/2)(1/2)(1/2)(1/2)= 1/16 or 6.25%
Answer:
- <u>59.0891 g (rounded to 4 decimal places)</u>
Explanation:
<em>Half-life time</em> of a radioactive substance is the time for half of the substance to decay.
Thus, the amount of the radioactive substance that remains after a number n of half-lives is given by:
Where:
- A is the amount that remains of the substance after n half-lives have elapses, and
- A₀ is the starting amount of the substance.
In this problem, you have that the half-live for your sample (polonium-210) is 138 days and the number of days elapsed is 330 days. Thus, the number of half-lives elapsed is:
- 330 days / 138 days = 2.3913
Therefore, the amount of polonium-210 that will be left in 330 days is:
(-14w) - (-3) - (-5w) equals
-9w + 3
or if what you're saying is
-14w - 3 - 5w it equals
-19w - 3
or if what youre saying is
(-14w - 3) - 5w it equals
-19w - 3
Answer:
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Step-by-step explanation: