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Svetlanka [38]
3 years ago
6

Can you help? photo is included​

Mathematics
1 answer:
laiz [17]3 years ago
3 0

Answer:

Step-by-step explanation:

f(x)=-4x+2

g(x)=x²+1

(gof)(x)=g(f(x))=g(-4x+2)=(-4x+2)²+2=16x²-16x+4+2=16x²-16x+6

(gof)(3)=16(3)²-16(3)+6=144-48+6=150-48=102

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Please help quickly needed !<br> thank you !
Dmitrij [34]

\Huge{\underline{\underline{\sf{\green{Answer:}}}}}

a) 2 (5x-3) = 24

= 10x -6 = 24

= 10x = 24+6

= 10x = 30

= x= 30/10

\boxed{\sf{x = 3}}

b) 5 (2x+1) = 50

= 10x+5=50

= 10x = 50-5

= 10x = 45

= x = 45/10

\boxed{\sf{x = 4.5}}

c) (3x+4)/2=9.5

= (3x+4)/2=95/10

( On cross multiplication )

= 10(3x+4) = 2×95

= 30x+40=190

= 30x=190-40

= 30x=150

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(on simplification)

\boxed{\sf{x = 5}}

d) (7+2x)/3=5

(On cross multiplication)

= 1(7+2x)=5(3)

= 7+2x=15

= 2x=15-7

= 2x=8

= x=8/2

(on dividing)

\boxed{\sf{x = 4}}

3 0
3 years ago
In order to be invited to tutoring or extension activities, a student's performance must be at least 20 points higher or lower t
marissa [1.9K]

Answer:

The inequality that represents p are p \geq 125 or p \leq 85.

Step-by-step explanation:

We are given that in order to be invited to tutoring or extension activities, a student's performance must be at least 20 points higher or lower than an average score. The average score is 105.

Let p = the scores for students who are eligible for tutoring or extension activities.

<u>The first condition</u> states that a student's performance must be at least 20 points higher than an average score, that means;

p \geq (105 + 20)

p \geq 125

Similarly, <u>the second condition</u> states that a student's performance must be at least 20 points lower than an average score, that means;

p \leq (105 - 20)

p \leq 85

So, the inequality that represents p are p \geq 125 or p \leq 85.

4 0
3 years ago
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13x−4=−36−27x+12: Distributive property  

13x−4=−24−27x: Combine like terms

40x=−20: Addition Property of equality

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So to answer all of them ( I don’t know if you want that it Imma do it anyways). For the first question: Name a radius - QR. For the second question: Name a diameter - NR. For question three: Name a chord - OP. For the last question: If the length of QS is 8 units, what is the length of NR: Since QS is a radius than the length of NR would be 16. Hope this helps!
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Answer:

he has 1 $ left

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