16x^2=9
x^2=9/18
x=sqrt(9/16)
x=3/4,-3/4
so the root of the quadratic equation are 3/4 and -3/4
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A few ways. you can enter it into a calculator for one, but the easiest way would be to reference a unit circle and look for an ordered pair where sin (the y value), is equal to -1/2
on a unit circle, the sin value is -1/2 at 7pi/6 and 11pi/6
because sin is the y value, it will additionally be in the quadrants III or IV based on the fact that (-1/2) as a sin value IS a negative and would have to be found in a quadrant in which sin is negative (the lower half of a coordinate plane, in this case)
Answer:
6
Step-by-step explanation:
it as a interior angle of a regular polygon is 23
14n + 21
Just distribute the 7 to the 2n and the 3.
7(2n + 3)
(7 * 2n) + (7 * 3)
14n + 21
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