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Illusion [34]
3 years ago
15

Every five years in March the population of a certain town is recorded. In 1995 the town had a population of 4,500 people. From

1995 to 2000, the population increased by 15%. From 2000 to 2005, the population decreased by 4%. What was the town's population on 2005
Mathematics
1 answer:
Mice21 [21]3 years ago
8 0

So, the town had a population on 4,500 people in 1995. Then from 1995 to 2000, the population increased by 15%.

Convert 15% to a decimal by dividing it by 100. Then, the population in 1995 by this decimal.

15% ÷ 100 = 0.15

4,500 × 0.15 = 675

Now, add this to the population in 1995.

4,500 + 675 = 5,175

This means that the town had a population of 5,175 people in 2000.

To calculate the town's population in 2005, repeat the same steps we took to find the population in 2000, except this time we will subtract instead of add since the population DECREASED.

4% ÷ 100 = 0.4

5,175 × 0.4 = 207

5,175 - 207 = 4,968

FINAL ANSWER:

The town had a population of 4,968 in 2005.

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Read more on Brainly.com - brainly.com/question/8884953#readmoreAnswer:

Step-by-step explanation:

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Answer:

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Explanation:

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Now find equation:

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\rightarrow \sf y - 21 = -7(x - (-3))

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2 years ago
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Please help!!!!!!! it would be very appreciated
Pani-rosa [81]

Answer:

x = 17.5 and y = 35

Step-by-step explanation:

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The table shows a student's proof of the quotient rule for logarithms.
nikklg [1K]

Answer:

The error is at step (3) .

The correct step (3) will be,

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Step-by-step explanation:

The error is at the step (3) , because the student has tried to prove the quotient rule of logarithms by using the property i.e., 'The quotient rule of logarithm' itself , i.e. ,by  assuming the property does hold before proving it. So, the proof is fallacious.

The correct step (3) will be,

\log_{b}(\frac {b^{x}}{b^{y}})

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