AB + CD = BC + DA
<span>Where A, B, C, and D are points on the quad, and AB is the length of the line A to B, etc. </span>
<span>Since you know three sides, you can easily solve for the fourth. </span>
Answer:
The top angle of the triangle is, X = 68°.
Step-by-step explanation:
Let there is a triangle named PQR with bottom corner angles ∠ P and ∠ Q and the ∠ R is the angle at the top.
Now, given that ∠ P = 31° and ∠ Q = 81° and we have to find out ∠ R i.e. X.
In Δ PQR, we know, ∠ P + ∠ Q + ∠ R = 180°
⇒ 31° + 81° + X = 180°
⇒ X = 68°
Therefore, the top angle of the triangle is 68°. (Answer)
Answer:
The roots of the equation 2m²+3=m are non-real roots.
Step-by-step explanation:
Given equation:
2m²+3=m
2m²-m+3=0
Here, from the equation we can obtain the following values:
a = 2, b = -1, c = 3
Discriminant of an equation is given as:
D = b²-4ac
= (-1)²-4(2)(3)
= 1 - 21
= -20
Discriminant can tell what kinds of roots the equation have.
In our case, the discriminant is less than 0.
When D < 0, the roots of the equation are complex conjugates.(non-real)
Answer: the answer is below
Step-by-step explanation:
its 4
2.5 i think
Answer:
Step-by-step explanation:
Let's use the definition of the Laplace transform and the identity given:![\mathcal{L}[t \cos 5t]=(-1)F'(s)](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5Bt%20%5Ccos%205t%5D%3D%28-1%29F%27%28s%29)
with ![F(s)=\mathcal{L}[\cos 5t]](https://tex.z-dn.net/?f=F%28s%29%3D%5Cmathcal%7BL%7D%5B%5Ccos%205t%5D)
.
Now, 
. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that 
.
Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that
.
Solving for F(s) on the last equation, 
, then the Laplace transform we were searching is 
