All categories

3 years ago

Convert 64 quarts to gallons

Mathematics

2 answers:

aleksley [76]3 years ago

7 0

Answer:

16 gallons

Step-by-step explanation:

Since 4 quarts is equal to a gallon, you should divide 64 quarts by 4 to get 16 gallons

RideAnS [48]3 years ago

5 0

Answer:

Containing in one gallon, there is 4 quarts.

I like to order my units preferably so I can understand better;

QUARTS 4 (x16) 64

________ = ______ = ______ so x = 16

GALLONS 1 (x16) x

You might be interested in

If sin theta = - squrt.3/2 and pi < theta < 3pi/2, what are the values of cos theta and tan theta?

Kryger [21]

So this first wants you to find where sin is √3/2 when θ is between π and 3π/2. θ would therefore be located at 2π/3.

Now plug in the value of θ for cosine:

cos (2π/3) = -1/2

And tangent:

tan (2π/3) = -√3/3

7 0

3 years ago

Read 2 more answers

A cart is coasting past Gordon. As it passes, he exerts a force on it. Whether the cart speeds up, slows down, or changes direct

Ksivusya [100]

Answer:

Direction

Step-by-step explanation:

Whether the car slows down or speeds up depends on the direction of the force applied, because if Gordon applied the force opposite the direction of the cart's movement, then the cart will slow down. If however, the force is applied in the direction of the carts movement, then the cart will speed up.

6 0

3 years ago

What are the solutions to the equation

frosja888 [35]

Answer:

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

Step-by-step explanation:

You have the quadratic function $2x^2-x+1=0$ to find the solutions for this equation we are going to use Bhaskara's Formula.

For the quadratic functions $ax^2+bx+c=0$ with $a\neq 0$ the Bhaskara's Formula is:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}$

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}$

It usually has two solutions.

Then we have $2x^2-x+1=0$ where a=2, b=-1 and c=1. Applying the formula:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}$

Observation: $\sqrt{-1}=i$

$x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}\\\\x_1=\frac{1+i.\sqrt{7}}{4}\\\\x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$

And,

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}\\\\x_2=\frac{-(-1)-\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_2=\frac{1-i.\sqrt{7} }{4}\\\\x_2=\frac{1}{4}-(\frac{\sqrt{7}}{4})i$

Then the correct answer is option C.

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

3 0

3 years ago

Plss help give brainiest if right!!

Nutka1998 [239]

The expression for the price Samantha paid for the candies is mc/n dollars.

We know that an expression, often known as a mathematical expression, is a finite collection of symbols that are well-formed in accordance with context-dependent principles.

Given that the number of candy that Samantha bought is m.

There are n candies in 1 pound.

i.e. 1 candy in 1/n pounds.

Then m candies in m/n pounds.

Also given that each pound costs c dollars.

So, m/n pound costs (m/n)*c dollars i.e. mc/n dollars.

We can conclude that the expression for the price Samantha paid for the candies is mc/n dollars.

Know more about expressions here -

brainly.com/question/13947055

#SPJ10

4 0

2 years ago

Y = 3.2 Solve the following system of equations by substitution. 3x -9x + 3y = 1

steposvetlana [31]

3x-9x+3(3.2)=1

3x-9x+9.6=1
-9.6. -9.6
-6x=-8.6
X=-8.6/-6=1.433333333

3 0

3 years ago

Read 2 more answers