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Alisiya [41]
3 years ago
8

If sinθ<0 and cosθ>0, then the terminal point determined by θ is in:

Mathematics
1 answer:
alukav5142 [94]3 years ago
5 0

Answer:

D.) Quadrant 4

Step-by-step explanation:

Sin theta < 0 tells us the angle is in quadrant 3 or 4

The y component is negative

Cos theta >0 tells us the angle is in quadrant 1 or 4

The x component is positive

Therefore theta must be in quadrant 4

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State the equation of the following graphs.<br> Someone please help ASAP
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Answer

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Explanation

A quadratic equation of the form y = ax^2 + bx + c

This written in complete the square form provides you with the vertex (either a maximum or minimum point depending on the equation).

This results in y = a(x + p) + q

Where - p is the x value and q is the y value of turning point.

For graph 22, x = -1 and y = -3

Therefore, the equation is of the form

y = a(x + 1) - 3 (*)

We still need the value a, this can be obtained by using the y-intercept we are given.

We are told x = 0 when y = -2

Substitute this in (*) equation:

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Therefore final equation is

y = 1(x +1) - 3

This should provide you with the train of thought of how the second question should also be tackled.

If unsure about why the equation
y = a(x + p) + q gives the vertex ask in comments I will respond
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I just did one of these. I guessed that normal form is


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