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pochemuha
3 years ago
15

Solve for a, 7-a=3 A.10 B.4 C.2 D5

Mathematics
2 answers:
Tcecarenko [31]3 years ago
5 0

Answer:

B

Step-by-step explanation:

Vika [28.1K]3 years ago
5 0

7 - a + 3

subtract 7 from both sides.

-a = 3 - 7

add like terms (3 + - 7)

-a = -4

divide both sides by -1. (remember that in front of the a, a 1 is there.)

a = 4

answer: b. 4

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And the missing number is 8, because 7 x 8 = 56.

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Which equation could be used to solve this problem? A number n is 8 less than the sum of 20 and 12. Find the number.
kifflom [539]

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3 years ago
Factor the polynomial, x2 + 5x + 6
patriot [66]

Answer:

Choice b.

x^{2} + 5\, x + 6 = (x + 3)\, (x + 2).

Step-by-step explanation:

The highest power of the variable x in this polynomial is 2. In other words, this polynomial is quadratic.

It is thus possible to apply the quadratic formula to find the "roots" of this polynomial. (A root of a polynomial is a value of the variable that would set the polynomial to 0.)

After finding these roots, it would be possible to factorize this polynomial using the Factor Theorem.

Apply the quadratic formula to find the two roots that would set this quadratic polynomial to 0. The discriminant of this polynomial is (5^{2} - 4 \times 1 \times 6) = 1.

\begin{aligned}x_{1} &= \frac{-5 + \sqrt{1}}{2\times 1} \\ &= \frac{-5 + 1}{2} \\ &= -2\end{aligned}.

Similarly:

\begin{aligned}x_{2} &= \frac{-5 - \sqrt{1}}{2\times 1} \\ &= \frac{-5 - 1}{2} \\ &= -3\end{aligned}.

By the Factor Theorem, if x = x_{0} is a root of a polynomial, then (x - x_0) would be a factor of that polynomial. Note the minus sign between x and x_{0}.

  • The root x = -2 corresponds to the factor (x - (-2)), which simplifies to (x + 2).
  • The root x = -3 corresponds to the factor (x - (-3)), which simplifies to (x + 3).

Verify that (x + 2)\, (x + 3) indeed expands to the original polynomial:

\begin{aligned}& (x + 2)\, (x + 3) \\ =\; & x^{2} + 2\, x + 3\, x + 6 \\ =\; & x^{2} + 5\, x + 6\end{aligned}.

4 0
3 years ago
Help me , this is my homework (Geometry) . I really need help
klemol [59]

8. Similar parts


\dfrac{6}{18} = \dfrac{AQ}{12}


AQ = 12(6)/18=12/3=4


Choice a


9. The Law of Sines says a:b:c and \sin A : \sin B \sin C are the same ratio.


The sines will go in order for acute angles, we have to convert 120 to its supplement 60 and then the order is 29,31,"60" or opposite sides JK, KL, JL


choice b


10.


DEF and FEG are supplments, FEG=180-DEF=180-114=66


DEF and HEG are opposite angles, so congruent HEG=DEF=114


chioce a


6 0
3 years ago
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