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stiv31 [10]
2 years ago
11

The vertex of a parabola represented by f(x)=x^2 - 4x + 3 has coordinates (2,-1). Find the coordinates of the vertex of the para

bola defined by g(x)=f(x-2). Explain how you arrived at your answer
Mathematics
1 answer:
Step2247 [10]2 years ago
7 0
f(x)=x^2-4x+3
a=1, b=-4, c=3
If the vertex has coordinates (2;-1)(p=2,q=-1) we can write vertex form of a parabola equation:
f(x)=a(x-p)^2+q
f(x)=1(x-2)^2-1

We need to put (x-2) at the place of (x) in f(x) equation to get g(x)
g(x)=1[(x-2)-2]^2-1
g(x)=(x-2-2)^2-1
g(x)=(x-4)^2-1
So:
p=4, q=-1

Vertex of the parabola defined by g(x)=f(x-2) has the vertex at \boxed{(4;-1)}

:)
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