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Goshia [24]
2 years ago
12

HELP ASAP!!! ILL GIVE LOTS OF POINTS AND BRAINLIST PLEASE SHOW HOW YOU GOT THE ANSWER!

Mathematics
1 answer:
Kruka [31]2 years ago
7 0

Answer: 27

Step-by-step explanation:

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What is the discriminant of the quadratic equation 0 = –x2 + 4x – 2?
Ber [7]

When the equation is of the form

... ax² +bx +c = 0

the discriminant is

... d = b² -4ac

Here, your equation is in the appropriate form, so we can identify

... a = -1, b = 4, c = -2

and calculate the discriminant as

... d = 4² - 4(-1)(-2) = 16 - 8 = 8

The discriminant is 8.

6 0
4 years ago
Twice a week a farmer supplies vegetables to 6 stores that she has an agreement with. Experience has shown that there is 20 % ch
olya-2409 [2.1K]

Answer:

12

Step-by-step explanation:

8 0
3 years ago
A medical researcher has two petri dishes containing viruses. Dish A has a population density of 1.2 viruses per square millimet
Lyrx [107]
<h3><u>Answer;</u></h3>

= 3,391 viruses

<h3><u>Explanation;</u></h3>
  • The population density is 1.2 viruses per square millimeter.
  • This means, each square millimeter is occupied by a population of 1.2 viruses.

Therefore; for an area of 2,826 square millimeters, there will be;

  = 2,826 multiplied by 1.2 viruses

 = 2,826 × 1.2

 = 3391.2 viruses,

and since we can have a fraction or decimal virus then the population would be <u>3391 viruses</u>

7 0
3 years ago
Read 2 more answers
12t - 4-7t = 5t-4
igor_vitrenko [27]

Answer:

infinitely many solutions

Step-by-step explanation:

12t-5t=7t-7t=0=-4t=-4, 4+-4=0 so 0=0

8 0
3 years ago
Simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B6a%5E2%20b%5E-%5E2%7D%7B8a%5E-%5E3%20b%5E3%7D" id="TexFormula1" title="\fra
romanna [79]

Answer:

3rd option

Step-by-step explanation:

using the rules of exponents

\frac{a^{m} }{a^{n} } = a^{(m-n)} : nm > n

\frac{a^{m} }{a^{n} } = \frac{1}{a^{(n-m)} } : n > m

\frac{6a^2b^{-2} }{8a^{-3b^3} } ← separate the variables

= \frac{6}{8} × \frac{a^2}{a^{-3} } × \frac{b^{-2} }{b^3}

= \frac{3}{4} × a^{2-(-3)} × \frac{1}{b^{3-(-2)} }

= \frac{3}{4} × a^{2+3} × \frac{1}{b^{3+2} }

= \frac{3}{4} × a^{5} × \frac{1}{b^{5} }

= \frac{3a^{5} }{4b^{5} }

4 0
2 years ago
Read 2 more answers
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