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Korvikt [17]
3 years ago
7

Will mark Brainliest

Mathematics
1 answer:
Ivahew [28]3 years ago
8 0

Answer:

57.39

[tex]440 \: ( 1 + \frac{5t}{46 + \: {t}^{2} } ) \\ 440 \: ( \frac{6t}{46 {t}^{2} } ) \: ( \: multiply \: 440 \times 6t) \\ \frac{2640}{46} \\ = 57.39 or 57.30

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How many solutions does the system have?
klio [65]

it have manny solution it depand on a method u are using

4 0
3 years ago
Maggie’s brother is 12 years younger that three times her age . The sun of their ages is 44 . How old is Maggie
meriva
I'm not sure if this is right but you can set up an equation and solve to find Maggie's age:

Maggie's brother's age = b
Maggie's age = m

b = 12 - 3m
44 = 12-3m
12-3m = 44
-12 -12
-3m = 32
÷ 3 ÷3
m = 10.67

So this would be Maggie's age

I hope this helped :)
7 0
4 years ago
What happens to the interval as the level of confidence is​ changed? Explain why this is a logical result.
Elan Coil [88]

Answer with explanation:

A x% confidence interval interprets the percentage of certainty that a person can believe that the true population parameter.

It is also represented as Point estimate ± Margin of error

Confidence level is proportional to the Margin of error.

  • As confidence level increases the error bound increases that makes the confidence interval broader.
  • As confidence level decreases the error bound decreases , making the confidence interval narrower.
6 0
3 years ago
Follow the steps to solve this equation:
saw5 [17]
4X-8=12
+8 +8

4x/4=20/4

X=5

5 0
3 years ago
Read 2 more answers
It turns out that (0.125)^3 can be written as 2^a for some integer a. Find a.
Ann [662]

Answer:

a=-9

Step-by-step explanation:

We begin with (0.125)^3

First, we can convert this decimal into a fraction

(\frac{1}{8} )^3

Now, we can simplify the denominator of the fraction

(\frac{1}{2^{3} } )^3

Next, we can remove the fraction by rewriting the fraction with a negative power.

(2^{-3} )^3

Lastly, we can remove the parenthesis by multiplying the powers together.

2^{-9}

This means that a=-9

4 0
3 years ago
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