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Zielflug [23.3K]
3 years ago
7

Help please, I’m timed.

Mathematics
1 answer:
Nadya [2.5K]3 years ago
4 0

Answer:

Final answer is A. P(A^c)=\frac{4}{7}

Step-by-step explanation:

From table we see that there are 7 places in the list.

Event A = The place is city.

Then A^c indicates the place is NOT city.

From table we see that there are 4 names "India, Peru, Canada, Mexico" which are not city.

Hence probability that the chosen place is not city is given by:

P(A^c)=\frac{4}{7}

Hence final answer is A. P(A^c)=\frac{4}{7}

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Y = x^2 + 11x + 24 = (x + 8)(x + 3)
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PQ = 1/2BC

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If the mean is 298 and standard deviation is 22 what is the probability that a random sample of 42 pregnancies has a mean gestat
anyanavicka [17]

Answer:

The probability is 0.9909.

Step-by-step explanation:

Test statistic (z) = (sample mean - population mean) ÷ (sd/√n)

sample mean = 290 days

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The cumulative area of the test statistic is the probability that the mean gestation period is less than 290 days. The cumulative area is 0.9909. Therefore the probability is 0.9909.

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Keegan is printing and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total
Katarina [22]

Answer:

t-shirts: 2790

profit: $12209

Step-by-step explanation:

Given  the function:

p(x) = -x³ + 4x² + x

we want to maximize it.

The following criteria must be satisfied at the maximum:

dp/dx = 0

d²p/dx² < 0

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Using quadratic formula:

x = \frac{-b \pm \sqrt{b^2 -4(a)(c)}}{2(a)}

x = \frac{-8 \pm \sqrt{8^2 -4(-3)(1)}}{2(-3)}

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Replacing into profit equation:

p(x) = -(2.79)³ + 4(2.79)² + 2.79 =  12.209

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Yes, it is.

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