Multiply 1/3 (X-2) by 9.

Mathematics

1 answer:

rosijanka [135]3 years ago

6 0

3x-6 Reduce #s with 3 (x-2)x3 and distribute 3 through the parentheses

You might be interested in

7x-3=-3+7x i neep help answer this please

erica [24]

Answer:

All real numbers are solutions.

Step-by-step explanation:

Let's solve your equation step-by-step.

7x− 3 = − 3 + 7x

Step 1: Simplify both sides of the equation.

7x − 3 = −3 + 7x

7x + −3 = −3 + 7x

7x − 3 = 7x − 3

Step 2: Subtract 7x from both sides.

7x− 3 −7x = 7x −3 −7x

−3 = −3

Step 3: Add 3 to both sides.

−3 + 3 = −3 + 3

0 = 0

7 0

3 years ago

Read 2 more answers

What is a four digit whole number that is divisble by 2

valentinak56 [21]

Answer:

any even number is divisible by 2.

Here's an example: 2222

There are lots of others as well.

3 0

3 years ago

Read 2 more answers

The height h of a projectile is a function of the time t it is in the air. the height in feet for t seconds is given by the func

alexgriva [62]

Domain means the values of independent variable(input) which will give defined output to the function.

Given:

The height h of a projectile is a function of the time t it is in the air. The height in feet for t seconds is given by the function

$h(t)=-16t^2 + 96t$

Solution:

To get defined output, the height h(t) need to be greater than or equal to zero. We need to set up an inequality and solve it to find the domain values.

$To \; find \; domain:\\\\h(t) \geq0\\\\-16t^2+96t \geq 0\\Factoring \; -16t \; in \; the \; left \; side \; of \; the \; inequality\\\\-16t(t-6) \geq 0\\Step \; 1: Find \; Boundary \; Points \; by \; setting \; up \; above \; inequality \; to \; zero.\\\\t(t-6)=0\\Use \; zero \; factor \; property \; to \; solve\\\\t=0 \; (or) \; t = 6\\\\Step \; 2: \; List \; the \; possible \; solution \; interval \; using \; boundary \; points\\(- \infty,0], \; [0, 6], \& [6, \infty)$

$Step \; 3:Pick \; test \; point \; from \; each \; interval \; to \; check \; whether \\\; makes \; the \; inequality \; TRUE \; or \; FALSE\\\\When \; t = -1\\-16(-1)(-1-6) \geq 0\\-112 \geq 0 \; FALSE\\(-\infty, 0] \; is \; not \; solution\\Also \; Logically \; time \; t \; cannot \; be \; negative\\\\When \; t = 1\\-16(1)(1-6) \geq 0\\80 \geq 0 \; TRUE\\ \; [0, 6] \; is \; a \; solution\\\\When \; t = 7\\-16(7)(7-6) \geq 0\\-112 \geq 0 \; FALSE\\ \; [6, -\infty) \; is \; not \; solution$