Answer:
Step-by-step explanation:
Given
7.2, a, b, 3 are in A.P
as
a, b, 3 are also in A.P
Putting
Now, plugging in
Therefore,
Answer:
<u>Answer (a):</u>
s + l = 22 ... (i)
43s + 75l = 1234 ... (ii)
<u>Answer (b)</u>
9 large dogs.
Step-by-step explanation:
Paws at Play made a total of $1234 grooming 22 dogs.
Paws at Play charges $43 to groom each small dog and;
$75 for each large dog.
Let the number of small dogs be 's'
And the number of large dogs be 'l'
<u>A system of equations will be:</u>
s + l = 22 ... (i)
43s + 75l = 1234 ... (ii)
Solving this set of simultaneous equations by elimination, we simply multiply (i) by 43 to get;
43s + 43l = 946 ... (i)
43s + 75l = 1234 ... (ii)
Subtracting (i) from (ii) we get;
32l = 288 , l = = 9
So there are 9 large dogs.
Answer:
not a solution
Step-by-step explanation:
y < 7x + 8
Substitute (2-,-6) into the inequality
-6 < 7(-2) +8
-6 <-14+8
-6 <-6
This is not true because they are equal not less than