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3 years ago

7

What is the value of x in the equation –x = 4 – 3x + 6?

2 answers:

Nataly [62]3 years ago

7 0

Remember you can do anything to an equaiton as long as you do it to both sides

-x=4-3x
add 3x both sides
3x-x=4+3x-3x
2x=4+0
2x=4
divide 2
2x/2=4/2
2/2x=2
1x=2
x=2

Dima020 [189]3 years ago

7 0

Answer:

The answer is x=5

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all shoes are 1/7 off of the original price. how much would a pair of shoes cost that were originally $35.00

yanalaym [24]

Answer:

35 diveded by 7=5 so 35 minus 5 = 30 so the shoes are 30.00

Step-by-step explanation:

4 0

2 years ago

Paul needs 40 pounds of 48% silver alloy to finish a collection of jewelry. How many pounds each of 45% silver alloy and 60% sil

Salsk061 [2.6K]

<span>Equation:
silver + silver = silver
0.45x + 0.60(40-x) = 0.48*40
----------------
45x + 60*40 - 60x = 48*40

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-15x = -12*40
x = (4/5)40
x = 32 lbs (amt of 45% slloy needed)
40-x = 8 lbs (amt of 60% alloy needed)</span>

8 0

3 years ago

Differentiate with respect to X <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%5Cfrac%7Bcos2x%7D%7B1%20%2Bsin2x%20%7D%20

Mice21 [21]

Power and chain rule (where the power rule kicks in because $\sqrt x=x^{1/2}$ ):

$\left(\sqrt{\dfrac{\cos(2x)}{1+\sin(2x)}}\right)'=\dfrac1{2\sqrt{\frac{\cos(2x)}{1+\sin(2x)}}}\left(\dfrac{\cos(2x)}{1+\sin(2x)}\right)'$

Simplify the leading term as

$\dfrac1{2\sqrt{\frac{\cos(2x)}{1+\sin(2x)}}}=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}$

Quotient rule:

$\left(\dfrac{\cos(2x)}{1+\sin(2x)}\right)'=\dfrac{(1+\sin(2x))(\cos(2x))'-\cos(2x)(1+\sin(2x))'}{(1+\sin(2x))^2}$

Chain rule:

$(\cos(2x))'=-\sin(2x)(2x)'=-2\sin(2x)$

$(1+\sin(2x))'=\cos(2x)(2x)'=2\cos(2x)$

Put everything together and simplify:

$\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{(1+\sin(2x))(-2\sin(2x))-\cos(2x)(2\cos(2x))}{(1+\sin(2x))^2}$

$=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{-2\sin(2x)-2\sin^2(2x)-2\cos^2(2x)}{(1+\sin(2x))^2}$

$=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{-2\sin(2x)-2}{(1+\sin(2x))^2}$

$=-\dfrac{\sqrt{1+\sin(2x)}}{\sqrt{\cos(2x)}}\dfrac{\sin(2x)+1}{(1+\sin(2x))^2}$

$=-\dfrac{\sqrt{1+\sin(2x)}}{\sqrt{\cos(2x)}}\dfrac1{1+\sin(2x)}$

$=-\dfrac1{\sqrt{\cos(2x)}}\dfrac1{\sqrt{1+\sin(2x)}}$

$=\boxed{-\dfrac1{\sqrt{\cos(2x)(1+\sin(2x))}}}$

5 0

3 years ago

The 3rd term and 7th terms of an arithmetic progression are 6 and 30 respectively

matrenka [14]

Answer:

Step-by-step

Create an algebraic equation. 6N-12. 6x1 - 12 = -6. So -6 is the first term.

6x10-12 = 48. So 48 is the 10th term

Hope it helps

Sorry if it’s unclear

5 0

3 years ago

Read 2 more answers

. Ms. Johnson owns a cabinet business that installs cabinets in kitchens. Her employees can install 2/3 of a

AnnZ [28]

Answer:

10/3 of a kitchen cabinet

Step-by-step explanation:

To make a full hour, 1/5 would be multiplied by 5- and so would their progress.

2/3 * 5 = 10/3, which is also an improper fraction.

8 0

2 years ago